Answer:
Explanation:
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<u>1. First find the density of your chain</u>
- Volume = displaced water volume
= Volume of Final level of water - initial level of water
= 20 ml - 15 ml = 5 ml
- Density = 66.7g / 5 ml = 13.34 g/ml
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<u>2. Second, write the denisty of the chain as the weighted average of the densities of the other metals:</u>
Mass of gold × density of gold + mass of other metals × density of other metals, all divided by the mass of the chain.
Calling x the amount of gold, then the amount of other metals is 66.7 - x:
![\dfrac{19.3\cdot x+9.7\cdot (66.7-x)}{66.7}=13.34](https://tex.z-dn.net/?f=%5Cdfrac%7B19.3%5Ccdot%20x%2B9.7%5Ccdot%20%2866.7-x%29%7D%7B66.7%7D%3D13.34)
![19.3x+635.66-9.7x=889.778](https://tex.z-dn.net/?f=19.3x%2B635.66-9.7x%3D889.778)
![9.6x=254.118\\\\x=26.47](https://tex.z-dn.net/?f=9.6x%3D254.118%5C%5C%5C%5Cx%3D26.47)
Then, there are 26.47 grams of gold in 66.7 grams of chain, which yields a percentage of:
- (26.47 / 66.7) × 100 = 39.7%
Answer:Yes, it is
Step-by-step explanation:
2^2+4(2)-12=0
4+8-12=0
12-12=0
0=0
Answer:
272.5 m²
Step-by-step explanation:
1/2x4x9=18
(9+18)/2=13.5. 13.5x11=148.5
(18+14)/2=16. 16x7=112
12+148.5+112= 272.5
Let it be x
Using basic proportionality theorem
![\\ \sf\longmapsto \dfrac{x}{10}=\dfrac{14}{7}](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20%5Cdfrac%7Bx%7D%7B10%7D%3D%5Cdfrac%7B14%7D%7B7%7D)
![\\ \sf\longmapsto \dfrac{x}{10}=2](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20%5Cdfrac%7Bx%7D%7B10%7D%3D2)
![\\ \sf\longmapsto x=10(2)](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20x%3D10%282%29)
![\\ \sf\longmapsto x=20](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20x%3D20)
Answer:
x^3 + 1
Step-by-step explanation:
Swap x and y and solve for y:
x =(y-1)^⅓
x³ = y-1
y = x³+1
f(x) = x³+1