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3 years ago

What are the domain and range of the mathematical function f(x)=x-3

Mathematics

1 answer:

vlabodo [156]3 years ago

7 0

Domain: All Real Numbers

Range: All Real Numbers

Further explanation:

Let us define domain and range first

Domain is the set of all possible inputs for a function on which the function is defined.

While range is the output of the function obtained by inputting domain

Here,

Given function is:

$f(x) =x-3$

The function will not be undefined on any input, so the domain of the function is all real numbers.

Similarly, the range will also be all real numbers as there is no input which makes it undefined.

Keywords: Domain, range of a function

Learn more about domain and range at:

#LearnwithBrainly

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The area of a circle is 497 cm2. What is the circumference, in centimeters? Express

SVEN [57.7K]

Answer:

14π

Step-by-step explanation:

Area πr^2= 49π sq cm

so r= 7 cm

perimeter= 2πr= 14π

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3 years ago

Write 5y-2=-9x+7 in standered form

bogdanovich [222]

$y = \frac{ - 9}{5} x + \frac{9}{5}$
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3 years ago

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Solve for x in the equation x^2-8x+41=0?

Angelina_Jolie [31]

X = [-(-8) +/- sqrt((-8)^2 -4*41)] / 2

x = ( 8 + sqrt (-100) / 2 and (8 - sqrt(-100) / 2

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3 years ago

If a cylinder has a height of 12 feet and a radius of 4 feet, what is its surface area (in square feet)? What is its volume (in

Zanzabum

The volume of the cylinder is 602.88 ft³.

The surface area of the cylinder is 301.44 ft²

<h3>How to find the volume and surface area of a cylinder?</h3>

volume of a cylinder = πr²h

volume of a cylinder = 3.14 × 4² × 12

volume of a cylinder = 3.14 × 16 × 12

volume of a cylinder = 602.88 ft³

Surface are of a cylinder = 2πr(r + h)

Surface are of a cylinder = 2 × 3.14 × 4(4 + 8)

Surface are of a cylinder = 25.12(12)

Surface are of a cylinder = 301.44 ft²

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2 years ago

Find y<br> y= |x−5| + |x+5| (if x>5)

velikii [3]

Answer:

$y=2x$ if $x>5$ .

Step-by-step explanation:

$|x-5|=x-5 \text{ if } x-5 \ge 0$ . This means when $x \ge 5$ .

$|x-5|=-(x-5) \text{ if } x-5 \le 0$ . This means when $x \le 5$ .

It doesn't matter where the 5 is included since either $x-5$ or $-(x-5)$ would product 0 at $x=5$ .

$|x+5|=x+5 \text{ if } x+5 \ge 0$ . This means when $x \ge -5$ .

$|x+5|=-(x+5) \text{ if } x+5 \le 0$ . This means when $x \le -5$ .

The same statement here about $x=-5$ as I about $x=5$ with the earlier expression.

So anyways we have $x>5$ .

This means $y=|x-5|+|x+5|$ can be rewritten as

$y=(x-5)+(x+5)=(x+x)+(-5+5)=2x+0=2x$ .

$y=2x$

6 0

3 years ago