Answer:
Molecular formula for Dioxybenzone is C₁₄H₁₂O₄
Explanation:
Percent composition:
In 100 g of compound → 4.92 g are H
In 100 g of compound → 26.8 g are O
In 100 g of compound → 68.28 g are C
Let's convert the mass to moles by molar mass:
4.92 g / 1 g/mol = 4.92 moles H
26.8 g / 16 g/mol = 1.67 moles O
68.28 g / 12 g/mol = 5.69 moles C
Now we can apply a rule of three:
100 g of compound have 4.92 moles H, 1.67 moles O, 5.69 moles C
244.25 g of compound must have:
(244.25 g . 4.92 m) / 100 g = 12 moles H
(244.25 g . 1.67 m) / 100 g = 4 moles O
(244.25 g . 5.69 m) / 100 g = 14 moles of C
