Question

How much of the 0.2M solution of NaCl did you dispense to measure out 3.0 grams of NaCl? Please give your answer in units of LITERS, however do not explicitly include any units in your answer.

Answer 1

The amount, in liters, of the 0.2M NaCl solution required to measure out 3.0 grams of NaCl is 0.25 Liter.

Stoichiometric problem

Recall that the molarity of a solution is the ratio of the number of moles of solutes in the solution to the volume of the solution.

Molarity = number of moles/volume in Liters

Thus, a 0.2M NaCl solution contains 0.2 moles of NaCl in 1 Liter of the solution.

But 3.0 grams of NaCl is needed. Recall that:

Number of moles = mass/ molar mass

3.0 grams of NaCl = 3.0 grams/58.88 g/mole = 0.051 moles

If 1 Liter of the solution contains 0.2 moles of NaCl, then the amount of the solution that will contain 0.051 moles (3.0 grams) will be:

               1 x 0.051/0.2 = 0.25 Liter

The volume of 0.2M NaCl solution required in order to measure out 3.0 grams of NaCl is 0.25 Liter.

More on stoichiometric problems can be found here: brainly.com/question/14465605

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