The amount, in liters, of the 0.2M NaCl solution required to measure out 3.0 grams of NaCl is 0.25 Liter.
<h3>Stoichiometric problem</h3>
Recall that the molarity of a solution is the ratio of the number of moles of solutes in the solution to the volume of the solution.
Molarity = number of moles/volume in Liters
Thus, a 0.2M NaCl solution contains 0.2 moles of NaCl in 1 Liter of the solution.
But 3.0 grams of NaCl is needed. Recall that:
Number of moles = mass/ molar mass
3.0 grams of NaCl = 3.0 grams/58.88 g/mole = 0.051 moles
If 1 Liter of the solution contains 0.2 moles of NaCl, then the amount of the solution that will contain 0.051 moles (3.0 grams) will be:
1 x 0.051/0.2 = 0.25 Liter
The volume of 0.2M NaCl solution required in order to measure out 3.0 grams of NaCl is 0.25 Liter.
More on stoichiometric problems can be found here: brainly.com/question/14465605
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