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4 years ago

Help help help with this question

Mathematics

1 answer:

ratelena [41]4 years ago

6 0

Your answer to that question would be the image A

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Mr.Nolans code for his atm card us a 4 digit number.The digits of the code are prjme factors of 84 listed from least to greatest

vlada-n [284]

1,2,3,4,6,7,12,14,21,28,42,84 are the prime factors of 84.

Therefore, the first four primes are: 1,2,3,7 so Mr. Nolans code is 1237.

3 0

3 years ago

Emergency!!!! Please Help!!! Time limit!!!!

almond37 [142]

Answer:

i cant see it very well it is too small can you zoom it in some thx :)

Step-by-step explanation:

6 0

3 years ago

The probability that a randomly chosen citizen-entity of Cygnus is of pension age† is approximately 0.7. What is the probability

victus00 [196]

Answer: 0.2401

Step-by-step explanation:

The binomial distribution formula is given by :-

$P(x)=^nC_xp^x(1-p)^{n-x}$

where P(x) is the probability of x successes out of n trials, p is the probability of success on a particular trial.

Given : The probability that a randomly chosen citizen-entity of Cygnus is of pension age† is approximately: p =0.7.

Number of trials : n= 4

Now, the required probability will be :

$P(x=4)=^4C_4(0.7)^4(1-0.7)^{4-4}\\\\=(1)(0.7)^4(1)=0.2401$

Thus, the probability that, in a randomly selected sample of four citizen-entities, all of them are of pension age =0.2401

5 0

3 years ago

If r = 4 and a6 = 192, what is the first term of the sequence?

blagie [28]

Answer:

Answer: Option c. 0.1875 is the first term of the sequence.

Step-by-step explanation:

In this question sixth term of a sequence is given as A(6)= 192

Ratio of terms is given as 4

And we have to calculate the first term of the sequence.

As per formula A(n) = A(1)× $r^{n-1}$

A(6) = $A(1)(r)^{6-1}$

192 = $A(1)4^{5}$

A(1) = $\frac{192}{4^{5} }$

= 192/1024

=0.1875

So the first term of the sequence will be 0.1875

5 0

3 years ago

A fruits seller bought some lemon for Re 1 for 15 lemon. if he sold all lemons at 25% profit, how many lemons were sold for Rs 1

Digiron [165]

Answer:

12 lemons

Step-by-step explanation:

CP of 15 lemon = ₹ 1

Profit = 25 %

SP of 15 lemons = $\frac{100+profit}{100}*CP$

$= \frac{125}{100}*1\\\\= \frac{5}{4}$

SP of 15 lemons = ₹ $\frac{5}{4}$

Number of lemon for ₹ $\frac{5}{4}$ = 15

Number of lemons for ₹ 1 = 15 ÷ $\frac{5}{4}$

$= 15 *\frac{4}{5}\\\\= 3*4\\\\= 12$

7 0

3 years ago