Answer:
The height of the new cones will be 16.5 inches.
Step-by-step explanation:
We know that,
The volume of a cone is,

Where, r is the radius of the cone,
h is the height of the cone,
In the original cone,
r = 22 inches,
h = 66 inches,
Thus, the volume would be,

Also, for the new cone,
r = 44 inches,
Let H be the height,
So, the volume of the new cone would be,

According to the question,



Hence, the height of the new cones will be 16.5 inches.
Area of cone = 1/3 base × height = 1/3 × 8 × 10 = approximately 26.7 m
Ans= approx. 26.4 m
Happy to help. Please mark as brainliest!
Answer:
last one
Step-by-step explanation:
anything with a ^2 is squared and ^3 is cubed
-5/3-6/d
Has to be 20 characters lol very sorry