Answer:
The percent error is 27.27%
Step-by-step explanation:
I did this by using the formula actual-estimated value/actual value
In this case it would be 3.75/13.75 and I got .2727 and then had to multiply by 100 (to find percent not decimal form) and got 27.27%
Since there are only 2/15 red marbles in the jar, to draw the first marble it would be a 2/15 chance, the next draw would only have 14 marbles, and only 1 red marble, giving you a 1/14 chance. Then you would just need to multiply those two together giving you 2/210, which you can simplify to 1/110
Note that
(4sqrt3)^2 = (2sqrt3)^2 + 6^2 [ 48 = 12 + 36] so the triangle is a right angled one with hypotenuse AB
So angle C = 90 degrees
sin A = 2 sqrt3 / 4 sqrt3 = 1.2 giving A = 30 degrees
and B = 90 - 30 = 60 degrees
A = 30, B = 60 and C = 90 degrees
now, we're making the assumption that the front and back of the tent are trapezoidal, Check the picture below.
![\textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} h=height\\ a,b=\stackrel{parallel~sides}{bases}\\[-0.5em] \hrulefill\\ h=32\\ a=23\\ b=36.5 \end{cases}\implies \begin{array}{llll} A=\cfrac{32(23+36.5)}{2}\implies A=952 \\\\\\ \stackrel{\textit{twice that much}}{2A=1904} \end{array}](https://tex.z-dn.net/?f=%5Ctextit%7Barea%20of%20a%20trapezoid%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7Bh%28a%2Bb%29%7D%7B2%7D~~%20%5Cbegin%7Bcases%7D%20h%3Dheight%5C%5C%20a%2Cb%3D%5Cstackrel%7Bparallel~sides%7D%7Bbases%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20h%3D32%5C%5C%20a%3D23%5C%5C%20b%3D36.5%20%5Cend%7Bcases%7D%5Cimplies%20%5Cbegin%7Barray%7D%7Bllll%7D%20A%3D%5Ccfrac%7B32%2823%2B36.5%29%7D%7B2%7D%5Cimplies%20A%3D952%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Btwice%20that%20much%7D%7D%7B2A%3D1904%7D%20%5Cend%7Barray%7D)
Its you will be found and the equation answer is 56
