Answer:It's 18
Step-by-step explanation:Multiply 7 and 6 to get 42
Subtract 10 from 13 to get 3
Divide 42 by 3 to get 14
Add 14 and 4 to get 18
The midpoint (W) of XY is also on segment PQ, so PQ is the bisector of XY.
Hope it helps you :)
For large sample confidence intervals about the mean you have:
xBar ± z * sx / sqrt(n)
where xBar is the sample mean z is the zscore for having α% of the data in the tails, i.e., P( |Z| > z) = α sx is the sample standard deviation n is the sample size
We need only to concern ourselves with the error term of the CI, In order to find the sample size needed for a confidence interval of a given size.
z * sx / sqrt(n) = width.
so the z-score for the confidence interval of .98 is the value of z such that 0.01 is in each tail of the distribution. z = 2.326348
The equation we need to solve is:
z * sx / sqrt(n) = width
n = (z * sx / width) ^ 2.
n = ( 2.326348 * 6 / 3 ) ^ 2
n = 21.64758
Since n must be integer valued we need to take the ceiling of this solution.
n = 22
Question 1 is A DEBIT CARD
Question 2 is A CHECKING ACCOUNT
