9514 1404 393
Answer:
y = 2x -5
Step-by-step explanation:
The parallel line will differ only in the value of c. That can be found using the given point.
y = mx +c
c = y -mx . . . . . . subtract mx to solve for c
c = 1 -2·3 = -5 . . . . . . the value of m is 2 in the given equation (x, y) = (3, 1)
The equation of the parallel line is ...
y = 2x -5
Answer:
(f - g)(3) = 6
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
f(x) = 4x - 2
g(x) = x + 1
<u>Step 2: Find</u>
<em>Find (f - g)(x)</em>
- Substitute: (f - g)(x) = 4x - 2 - (x + 1)
- Distribute -1: (f - g)(x) = 4x - 2 - x - 1
- Combine like terms: (f - g)(x) = 3x - 3
<em>Find (f - g)(3)</em>
- Substitute: (f - g)(3) = 3(3) - 3
- Multiply: (f - g)(3) = 9 - 3
- Subtract: (f - g)(3) = 6
<span>Acceleration of a passenger is centripetal acceleration, since the Ferris wheel is assumed at uniform speed:
a = omega^2*r
omega and r in terms of given data:
omega = 2*Pi/T
r = d/2
Thus:
a = 2*Pi^2*d/T^2
What forces cause this acceleration for the passenger, at either top or bottom?
At top (acceleration is downward):
Weight (m*g): downward
Normal force (Ntop): upward
Thus Newton's 2nd law reads:
m*g - Ntop = m*a
At top (acceleration is upward):
Weight (m*g): downward
Normal force (Nbottom): upward
Thus Newton's 2nd law reads:
Nbottom - m*g = m*a
Solve for normal forces in both cases. Normal force is apparent weight, the weight that the passenger thinks is her weight when measuring by any method in the gondola reference frame:
Ntop = m*(g - a)
Nbottom = m*(g + a)
Substitute a:
Ntop = m*(g - 2*Pi^2*d/T^2)
Nbottom = m*(g + 2*Pi^2*d/T^2)
We are interested in the ratio of weight (gondola reference frame weight to weight when on the ground):
Ntop/(m*g) = m*(g - 2*Pi^2*d/T^2)/(m*g)
Nbottom/(m*g) = m*(g + 2*Pi^2*d/T^2)/(m*g)
Simplify:
Ntop/(m*g) = 1 - 2*Pi^2*d/(g*T^2)
Nbottom/(m*g) = 1 + 2*Pi^2*d/(g*T^2)
Data:
d:=22 m; T:=12.5 sec; g:=9.8 N/kg;
Results:
Ntop/(m*g) = 71.64%...she feels "light"
Nbottom/(m*g) = 128.4%...she feels "heavy"</span>
<h3>52.68 feet per hour = 10.536 inches per minutes</h3>
<h3>Further explanation</h3>
Acceleration is rate of change of velocity.
<em>a = acceleration ( m/s² )</em>
<em>v = final velocity ( m/s )</em>
<em>u = initial velocity ( m/s )</em>
<em>t = time taken ( s )</em>
<em>d = distance ( m )</em>
Let us now tackle the problem !
If the dwarf seahorse hippocampus zosterae swims at a rate of 52.68 feet per hour , then :
<h3>Learn more</h3>
<h3>Answer details</h3>
Grade: High School
Subject: Physics
Chapter: Kinematics
Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate
