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lara [203]
3 years ago
11

What should I do here

Mathematics
1 answer:
gayaneshka [121]3 years ago
6 0
Identify any pairs of angles that their sum is 90°
You might be interested in
1. 7:4 = 21:x; what is the value of x?<br> A. 12<br> B. 10<br> C. 8<br> D. 6<br> E. 4<br> 8.
Soloha48 [4]

Answer:

x = 12

I hope it's helps you

8 0
3 years ago
a baseball team scored the following number of runs in its game this season: 6, 2, 5, 9, 11, 4, 5, 8, 6, 7, 5. there is one more
frez [133]
After the season, 12 games would be played, and you need to know this to work out the mean
Let's call the number of points needed for a 6 point average 'x'
The mean would be: 6 + 2 + 5 + 9 + 11 + 4 + 5 + 8 + 6 + 7 + 5 + x = 12 * 6
Simply put:
68 + x = 72
Then simplify it
x = 4
They would need 4 points to end the season with an average of 6 points

7 0
3 years ago
Evaluate the expression when m=4 and n=9 5m-n
Zigmanuir [339]
 5m-n
Just replace m with 4 and n with 9
5(4)-9=20-9=11
6 0
3 years ago
Given <br><img src="https://tex.z-dn.net/?f=%20log_%7B2%7D%28x%29%20%20%3D%20%20%5Cfrac%7B3%7D%7B%20log_%7Bxy%7D%282%29%20%7D%20
Naily [24]

Answer:

\displaystyle y = x^{-\frac{2}{3}}

Step-by-step explanation:

<u>Logarithms</u>

Some properties of logarithms will be useful to solve this problem:

1. \log(pq)=\log p+\log q

2. \displaystyle \log_pq=\frac{1}{\log_qp}

3. \displaystyle \log p^q=q\log p

We are given the equation:

\displaystyle \log_{2}(x) = \frac{3}{ \log_{xy}(2) }

Applying the second property:

\displaystyle  \log_{xy}(2)=\frac{1}{ \log_{2}(xy)}

Substituting:

\displaystyle \log_{2}(x) = 3\log_{2}(xy)

Applying the first property:

\displaystyle \log_{2}(x) = 3(\log_{2}(x)+\log_{2}(y))

Operating:

\displaystyle \log_{2}(x) = 3\log_{2}(x)+3\log_{2}(y)

Rearranging:

\displaystyle \log_{2}(x) - 3\log_{2}(x)=3\log_{2}(y)

Simplifying:

\displaystyle -2\log_{2}(x) =3\log_{2}(y)

Dividing by 3:

\displaystyle \log_{2}(y)=\frac{-2\log_{2}(x)}{3}

Applying the third property:

\displaystyle \log_{2}(y)=\log_{2}\left(x^{-\frac{2}{3}}\right)

Applying inverse logs:

\boxed{y = x^{-\frac{2}{3}}}

7 0
3 years ago
What is the point slope form of the points?
Darina [25.2K]

the equation of a line in point-slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

to calculate m use the gradient formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (- 4, - 1) and (x₂, y₂) = (1 1/2, 2 )

m = \frac{2+1}{11/2+4} = \frac{3}{5 1/2} = \frac{6}{11}

using (a, b) = (- 4, - 1), then

y + 1 = \frac{6}{11}(x + 4)


6 0
3 years ago
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