Step-by-step explanation:
That is what your line should look like :)
Answer:
The percentage of the simulations of two games that the football player would most likely get a touchdown in each of the two games = 15.21%
Step-by-step explanation:
The probability of scoring a touchdown in one game for the football player = 39% = 0.39
Probability of scoring a touchdown in each of the two consecutive games = (Probability of scoring a touchdown in the first game) × (Probability of scoring a touchdown in the second game)
Since the probability of scoring a touchdown in each game the football player plays in is independent of one another.
Probability of scoring a touchdown in the first game = Probability of scoring a touchdown in the second game = 0.39
Probability of scoring a touchdown in each of the two consecutive games = 0.39 × 0.39 = 0.1521
If 100 simulations of the two games are made, the player scores in each of the two games in 15.21 of them, hence, the percentage of the simulations that the football player would most likely get a touchdown in each of the two games = 15.21%
Hope this Helps!!
Answer:(2/5)j^2
Step-by-step explanation:
Answer:
The first is 0.046 and the second is 0.033
Step-by-step explanation:
Opening brackets;
18p+9-3p=4p-6
18p-3p+9=4p-6
15p+9=4p-6
Putting like terms together;
15p-4p=-6-9
11p=-15
p=
