Answer:
33
Step-by-step explanation:
The graphs are curved, not segments ending in a point.
http://www.wolframalpha.com/input/?i=plot+y+%3D+sin+x+for+-3.2+%3C+x+%3C+3.2+and+-1.1+%3C+y+%3C+1.2
Answer:
2
Step-by-step explanation:
Solve. To do so, change the division sign into a multiplication sign, and flip the second fraction:
(2/3)/(1/3) = (2/3) x (3/1)
Multiply across:
(2 * 3)/(3 * 1) = (6)/(3)
Simplify:
6/3 = 2
2 is your answer.
~
Answer:
a) 30 kangaroos in 2030
b) decreasing 8% per year
c) large t results in fractional kangaroos: P(100) ≈ 1/55 kangaroo
Step-by-step explanation:
We assume your equation is supposed to be ...
P(t) = 76(0.92^t)
__
a) P(10) = 76(0.92^10) = 76(0.4344) = 30.01 ≈ 30
In the year 2030, the population of kangaroos in the province is modeled to be 30.
__
b) The population is decreasing. The base 0.92 of the exponent t is the cause. The population is changing by 0.92 -1 = -0.08 = -8% each year.
The population is decreasing by 8% each year.
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c) The model loses its value once the population drops below 1/2 kangaroo. For large values of t, it predicts only fractional kangaroos, hence is not realistic.
P(100) = 75(0.92^100) = 76(0.0002392)
P(100) ≈ 0.0182, about 1/55th of a kangaroo
