Question

Write the equation of a line that passes through the points (-1, -4) and (1, 3).

Answer 1

Answer:

y=3.5x-.5

Step-by-step explanation:

Answer 2

Answer:

$y=\frac{7}{2} x-\frac{1}{2}$

OR

2y=7x-1

Step-by-step explanation:

(-1,-4)  (1,3)

step1: find the gradient m.

$m=\frac{y2-y1}{x2-x1}$

FOR (-1,-4) -1=x1   and  -4=y1

FOR (1,3)    1=x2   and   3=y2

SO,

$m=\frac{3-(-4)}{1-(-1)} =\frac{7}{2}$

step2: identify a and b for any point.

I will use (1,3)  1=a   and   3=b

step3: sub the values in the equation y-b=m(x-a) to get the equation of the line.

y-b=m(x-a)

y-3=$\frac{7}{2}$(x-1)

(times $\frac{7}{2}$ by the bracket)

y-3=$\frac{7}{2}x-\frac{7}{2}$

(add 3 for both sides)

$y=\frac{7}{2} x-\frac{1}{2}$

the answer is:

$y=\frac{7}{2} x-\frac{1}{2}$

OR

(you can multiply 2 for both sides to get rid of the fraction)

2y=7x-1