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2 years ago

14. The summer sports training camp has a

Mathematics

1 answer:

denpristay [2]2 years ago

5 0

Answer:

x is less than or equal to 165

Step-by-step explanation:

If you think about it 250-85 is 165 so technically you could have less than or equal to 165 students participating still!

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For every $3.00 the 5th grade raise, the 6th grade raises $5.00. If the 5th grades raises $36.00, how much does the 6th grade ra

frutty [35]

The sixth graders raised $60

7 0

2 years ago

Read 2 more answers

Logan wants to have $130,000 to pay for a surgery on his retractable forearm claws in 30 months. If he can invest money in an ac

dangina [55]

Answer: $107,836.69 or about $107,837 (to the nearest dollar)

Step-by-step explanation:

Formula to the accumulated amount received after investing principal amount (P) at rate of interest (r) compounded monthly for t months :

$A=P(1+\dfrac{r}{12})^{t}$

As per given , A = $130,000

r= 7.5% = 0.075

t= 30 months

Now,

$130000=P(1+\dfrac{0.075}{12})^{30}\\\\\Rightarrow 130000=P(1+0.00625)^{30}\\\\\Rightarrow 130000=P(1.00625)^{30}\\\\\Rightarrow 130000=P \times1.20552661036\\\\\Rightarrow\ P=\dfrac{130000}{1.2055266}=107,836.69$

Hence he need to invest $107,836.69 .

8 0

3 years ago

How do you solve: secx=-5/2, tanx<0<br><br> Find all six trig functions

Brut [27]

Answer:

sec theta = (sqrt24/5) cos theta = -2/5 tan theta = (-[sqrt 21]/2) sec theta = 5/2 csc theta = (5sqrt21)/21 cot theta = (-2sqrt21)/21

Step-by-step explanation:

During the problem, secx = -5/2, we can assume that as cos = -2/5. -2 = x. 5 = r. find for Y with: x^2+y^2=r^2. After that, plug in for the variables and you get all the answers. Rationalize the square roots, don't forget.

5 0

2 years ago

A circle with a circumference of 51 inches to find the area

Kaylis [27]

$\textit{circumference of a circle}\\\\ C=2\pi r~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ C=51 \end{cases}\implies 51=2\pi r\implies \boxed{\cfrac{51}{2\pi }=r} \\\\[-0.35em] ~\dotfill\\\\ \textit{area of a circle}\\\\ A=\pi r^2\qquad \implies A=\pi \left( \cfrac{51}{2\pi } \right)^2\implies A=\cfrac{51^2}{2^2\pi }\implies A\approx 206.98$

4 0

2 years ago

A garden has width of <img src="https://tex.z-dn.net/?f=%5Csqrt13" id="TexFormula1" title="\sqrt13" alt="\sqrt13" align="absmidd

inessss [21]

Answer:

perimeter of the garden=2(length+width)

=2(7√13+√13)

=2(8√13)

=16√13

4 0

2 years ago