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frosja888 [35]
1 year ago
12

If m∠F = 90° and m∠G = 70°, then ∠F and ∠G are not supplementary.

Mathematics
1 answer:
miss Akunina [59]1 year ago
5 0

a) Proof by contradiction is different from traditional proof as it accepts a single example showing that a statement is false, instead of having the need to derive a general relationship for all input values.

b) The statement is true by contradiction as the sum of the measures is of 160º, and not 180º.

<h3>What are supplementary angles?</h3>

Two angles are called supplementary angles if the sum of their measures has a value of 180º.

The measures of the angles in this problem are given as follows:

  • m∠F = 90°.
  • m∠G = 70°.

Then the sum of the measures of this angles is given as follows:

90 + 70 = 160º.

Which is a different sum of 160º, confirming the statement that the angles are not supplementary by contradiction.

A similar problem, involving proof by contradiction and supplementary angles, is presented at brainly.com/question/28889480

#SPJ1

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Daniela invested a total of $50,000, some in a certificate of deposit (CD) and the remainder in bonds. The amount invested in bo
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Answer:

The amount invested in bonds = 35,000

The amount invested in CD = 15,000.

Step-by-step explanation:

The total amount that Daniela invested is $50,000, this means if we call the amount invested in bonds b, and the amount invested in CD d, then we have:

b+d=50,000 this says the total amount Daniela invested is $50,000.

And since the amount invested in bonds b is $5,000 more than twice the amount Daniela put into the CD, we have:

b=5,000+2d.

Thus, we have two equations and two unknowns b and d:

(1). b+d=50,000

(2). b=5,000+2d,

and we solve this system by substituting b from the second equation into the first:

b+d=50,000\\5,000+2d+d=50,000\\3d=45,000\\\\\boxed{d=15,000}

or, the amount invested in CD is $15,000.

With the value of d in hand, we now solve for b from equation(2):

b=5,000+2d\\b=5000+2(15,000)\\\boxed{b=35,000}

or, the amount invested in bonds is $35,000.

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Step-by-step explanation:


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<h2>1)</h2>

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This must be true for some value of x, since we have a quantity squared yielding a positive number, and since the equation is of second degree,there must exist 2 real roots.

\sqrt{(x - 4) {}^{2} }  =  ± \sqrt{36}  \\x - 4 = ±6 \\ x _{1}- 4 = 6 \:  \:  \:  \:  \:  \:  \: \:  \:  \:  x _{2}- 4 =  - 6 \\ x_{1} = 6 + 4 \:  \:  \:  \:  \:  \:  \:  \:  \:  \: x_{2} =  - 6 + 4 \\ x_{1} = 10 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \: \:  \: x_{2} =  - 2

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Well he started off correct to the point of completing the square.

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