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2 years ago

Write a ratio expressing the slope of line n.

Mathematics

1 answer:

Arada [10]2 years ago

4 0

The slope or gradient of a line is a number that describes both the direction and the steepness of the line. To calculate the slope of a line, you take the ratio of the change of the two points. It is expressed as follows:

slope = Δy / Δx
slope = y2 - y1 / x2 - x1

You take two points from the graph and calculate using the equation above. Hope this helps. Have a nice day.

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Quick algebra 1 question for 50 points!

Mumz [18]

Answer:

y is equal to 24

Step-by-step explanation:

If y is directly proportional to x when x is equal to 5 and y is 12, then when you multiply 5 by 2 which is 10, y will be proportional to that when you multiply 12 by 2 which is 24

7 0

1 year ago

Read 2 more answers

Write and solve an equation to find the values of d and w .

NNADVOKAT [17]

Answer:

d = 65°

w = 55°

Step-by-step explanation:

m∠DAC +∠m∠CAB = 60

m∠DAC + 35 = 60

m∠DAC = 25

m∠DAC + d = 90

25 + d = 90

d = 65°

m∠GAF + w + d = 180

60 + w + 65 = 180

w + 125 = 180

w = 55°

6 0

2 years ago

Find the surface area of the prism. 2 om Som 17 cm lem?

fomenos

Your answer is 12950

4 0

2 years ago

"Find an integer, x, such that 5, 10, and x represent the lengths of the sides of an acute triangle.

Contact [7]

A, b, c - the lengths of the sides of the triangle
and a ≤ b ≤ c
then:
a + b > c and if the triangle is an acute triangle then a² + b² > c².

$1^o\\5\leq10\leq x\\\\\left\{\begin{array}{ccc}5+10 \ \textgreater \ x\\5^2+10^2 \ \textgreater \ x^2\end{array}\right\to\left\{\begin{array}{ccc}x \ \textless \ 15\\ x^2 \ \textless \ 125\end{array}\right\to\left\{\begin{array}{ccc}x \ \textless \ 15\\ x \ \textless \ \sqrt{125}\approx11.1\end{array}\right\\\\\boxed{x=11}\\\\2^o\\5\leq x\leq10\\\\\left\{\begin{array}{ccc}5+x \ \textgreater \ 10\\ 5^2+x^2 \ \textgreater \ 10^2\end{array}\right\to\left\{\begin{array}{ccc}x \ \textgreater \ 5\\ x^2 \ \textgreater \ 75\end{array}\right\to\left\{\begin{array}{ccc}x \ \textgreater \ 5\\ x \ \textgreater \ \sqrt{75}\approx8.7\end{array}\right\\\boxed{x=9}$

$3^o\\x\leq5\leq10\\\\\left\{\begin{array}{ccc}x +5 \ \textgreater \ 10\\ x^2+5^2 \ \textgreater \ 10^2\end{array}\right\to\left\{\begin{array}{ccc}x \ \textgreater \ 5\\ x^2 \ \textgreater \ 75\end{array}\right\to\left\{\begin{array}{ccc}x \ \textgreater \ 5\\ x \ \textgreater \ \sqrt{75}\approx8.7\end{array}\right\\\boxed{x\in\O}\\\\Answer:\boxed{x=9\ or\ x=11}\to your\ answer:\boxed{\boxed{x=11}}$

8 0

3 years ago

Read 2 more answers

Jim's speedboat can travel 24 miles upstream against a 4 mph current. In the same amount of time it travels 26 miles

8_murik_8 [283]

Answer:

speed of the boat = 100 mph

Step-by-step explanation:

Let x = speed of the boat

upstream speed = x - 4

downstream speed = x + 4

time = 24/(x - 4) = 26/(x + 4)

Cross multiply:

24(x + 4) = 26(x - 4)

24x + 96 = 26x - 104

104 + 96 = 26x - 24x

200 = 2x

x = 100 mph

8 0

1 year ago