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FrozenT [24]
3 years ago
6

Your personal library contains books written by 165 authors. 60% of the authors are men. 40% of the authors write only nonfictio

n works. Also, 40 of the male authors write only nonfiction works. Assuming that your library has only one book by each author, what is the probability that a book picked at random is either a work written by an author who writes only nonfiction or a work written by a man?
Mathematics
1 answer:
Ludmilka [50]3 years ago
3 0
Lets discern the infomation:

number_men = 165*0.6 = 99

so there are 99 men

non_fiction = 165 * 0.4 = 66

so 66 authors write non-fiction.

men writing non-fiction are 40, so 59 men write fiction, and 26 women write non-fiction.

probability of author non-fiction or man?
non-fiction: 40 men + 26 women = 66 total
man writers = 99

so in total 99 man + 26 women = 115 authors

hence the probability is:
115/165 = 69.6%
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Please help!!!!!!!!!!
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2/25 of the dogs.

Step-by-step explanation:

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3 years ago
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If anyone is good at geometry, pls help :)
Vadim26 [7]

Answer:

<u>Segment</u><u> </u><u>Addition</u><u> </u><u>Postulate</u>

<u>BC</u> + <u>AB</u> = <u>CA</u> [BOTH answers]

<u>Application</u><u> </u><u>with</u><u> </u><u>Midpoint</u>

<u>BC</u> = <u>BA</u>

1a) 9 = <em>x</em>

1b) 34 = FA

1c) 3 = AT

2a) 11 = <em>x</em>

2b) 37 = BO

2c) 37 = OX

2d) 74 = BX

Step-by-step explanation:

The Segment Addition Postulate is basically saying that if

___

point <em>B</em><em> </em>is in between <em>AC</em><em> </em>[NOT<em> </em>the <em>midpoint</em><em> </em>(or halfway)],<em> </em>then both segments [AB and BC] would make up the whole thing [CA, or vice versa]. They are just explaining it in two unique ways you can word it.

The Midpoint Application tells you that if point <em>B</em><em> </em>is a

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<em>midpoint</em><em>,</em><em> </em>meaning <em>B</em> is halfway in between <em>AC</em><em>,</em><em> </em>then both segments [AB and BC] are congruent to each other.

1a) 37 = [2<em>x</em> - 15] + [3<em>x</em> + 7]

37 = 5<em>x</em> - 8

+ 8 + 8

____________

45 = 5<em>x</em>

___ ___

5 5

9 = <em>x</em>

1b) Solving for FA

3(9) + 7 = 27 + 7 = 34

1c) Solving for AT

2(9) - 15 = 18 - 15 = 3

This obviously had to be the answer because 3 + 34 = 37.

2a) 2<em>x</em> +15 = 4<em>x</em> - 7

- 4<em>x</em> - 4<em>x</em>

_________________

-2<em>x</em> + 15 = -7

- 15 -15

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-2<em>x</em> = -22

<em>x</em><em> </em>= 11

2b) Solving for BO

4(11) - 7 = 44 - 7 = 37

2c) Solving for OX

2(11) + 15 = 22 + 15 = 37

2d) Solving for BX

2 \times 37 = 74

I am joyous to assist you anytime.

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A.  

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The first option is correct.

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