Answer:
Can't tell if it went through...
1. Shop A = 2x
2. Shop B = 2x - 580
3. Total = Shop A + Shop B
1949 = 2x + 2x - 580
4. Combine like terms
2x + 2x = 4x
1949 = 4x - 580
5. Add 580 to both sides (to remove -580 from right side)
1949 + 580 = 4x - 580 + 580
2529 = 4x
6. Divide both sides by 4 (to get x)
2529 / 4 = 4x / 4
632.25 = x
7. Shop A = 2x
2 * 632.25 = 1264.50
Shop A = 1264.50
8. Shop B = 2x - 580
2 * 632.25 - 580 = 684.50
Shop B = 684.50
Check: Shop A + Shop B = 1949
1264.50 + 684.50 = 1949
Shop A = 1264.50
Shop B = 684.50
Step-by-step explanation:
The answer would look something like this:
There could also have a simplified version.
I hope this helps.
Answer:
1st Question
A. 85
2nd Question
B. 71
Step-by-step explanation:
1st Question
{90 + 94 + 96 + 90} = 370/4 = 92.5
{95 + 99} = 194/2 = 97
{87 + 75 + 82 + 85} = 329/4 = 82.25
{71} = 71/1 = 71
.20(92.5) +.25(97) +.30(82.25) +.25(71) = 85.175 Rounded-up = 85
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2nd Question
.10(95) +.20(80) +.50(67) +.20(60) = 71
Answer:
it will be 35720 . I hope my answer is correct
By using the concept of uniform rectilinear motion, the distance surplus of the average race car is equal to 3 / 4 miles. (Right choice: A)
<h3>How many more distance does the average race car travels than the average consumer car?</h3>
In accordance with the statement, both the average consumer car and the average race car travel at constant speed (v), in miles per hour. The distance traveled by the vehicle (s), in miles, is equal to the product of the speed and time (t), in hours. The distance surplus (s'), in miles, done by the average race car is determined by the following expression:
s' = (v' - v) · t
Where:
- v' - Speed of the average race car, in miles per hour.
- v - Speed of the average consumer car, in miles per hour.
- t - Time, in hours.
Please notice that a hour equal 3600 seconds. If we know that v' = 210 mi / h, v = 120 mi / h and t = 30 / 3600 h, then the distance surplus of the average race car is:
s' = (210 - 120) · (30 / 3600)
s' = 3 / 4 mi
The distance surplus of the average race car is equal to 3 / 4 miles.
To learn more on uniform rectilinear motion: brainly.com/question/10153269
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