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natulia [17]
2 years ago
7

Help me plz with my hw

Mathematics
1 answer:
inna [77]2 years ago
6 0
Circumference is found with the formula

c = pi × d

d is diameter and we will use 3.14 for pi.

The diameter is the measure across the center of the circle. In the first problem, you are given the radius, so we have to multiply by 2 to get the diameter. Then we can use the formula.

12.4 in × 2 = 24.8 in (that's the diameter)

c = pi × D
c = 3.14 × 24.8
c = 77.872 inches

circumference is 77.872 inches.

Try the other problems on your own. They are just like this one. Just make sure they are giving you the diameter and not the radius. Post if you have problems.
You might be interested in
I don’t understand number 89! please help I have a test tomorrow!
Rainbow [258]
V = rw

where; v = velocity , r = radius , w = angular speed

you're given the diameter = 0.5 miles so the radius = 0.25 miles

180 = (0.25)w
180/0.25 = w
720 radians per hour = w

2pi radians in 1 revolution

720 rad/hr * 1 rev / 2pi rad = 720/2pi rev/hr
= 114.6 rev/hr
8 0
3 years ago
I need some help on this :)
Softa [21]
Photo math helps it worked for me so might help you :)
6 0
2 years ago
Can 3.65909090909 be expressed as a fraction whose denominator is a power of 10? Explain.
GuDViN [60]
\bf 3.659\textit{ can also be written as }\cfrac{3659}{1000}\textit{ therefore }3.6590909\overline{09}\\\\
\textit{can be written as }\cfrac{3659.0909\overline{09}}{1000}

notice above, all we did, was isolate the "recurring part" to the right of the decimal point, so the repeating 09, ended up on the right of it.

now, let's say, "x" is a variable whose value is the recurring part, therefore then

\bf \cfrac{3659.0909\overline{09}}{1000}\qquad \boxed{x=0.0909\overline{09}} \qquad \cfrac{3659+0.0909\overline{09}}{1000}\implies \cfrac{3659+x}{1000}

now, the idea behind the recurring part is that, we then, once we have it all to the right of the dot, we multiply it by some power of 10, so that it moves it "once" to the left of it, well, the recurring part is 09, is two digits, so let's multiply it by 100 then, 

\bf \begin{array}{llllllll}
100x&=&09.0909\overline{09}\\
&&9+0.0909\overline{09}\\
&&9+x
\end{array}\quad \implies 100x=9+x\implies 99x=9
\\\\\\
x=\cfrac{9}{99}\implies \boxed{x=\cfrac{1}{11}}\\\\
-------------------------------\\\\
\cfrac{3659.0909\overline{09}}{1000}\qquad \boxed{x=0.0909\overline{09}} \quad \cfrac{3659+0.0909\overline{09}}{1000}\implies \cfrac{3659+x}{1000}
\\\\\\
\cfrac{3659+\frac{1}{11}}{1000}

and you can check that in your calculator.
8 0
3 years ago
What is 363 rounded to the nearest ten and hundred
anyanavicka [17]
3 is less than 5, so rounded to the nearest ten is 360.

6 is greater than 5, so rounded to the nearest hundred, our answer is 400.
4 0
3 years ago
Read 2 more answers
Please help me factor this!! Thanks!
Goryan [66]
We need to find two numbers that multiply to 24 (last coefficient) and add to 10 (middle coefficient). Through trial and error, the two values are 6 and 4

6 + 4 = 10
6*4 = 24

So we can break up the 10ab into 6ab+4ab and then use factor by grouping

a^2 + 10ab + 24b^2
a^2 + 6ab + 4ab + 24b^2
(a^2+6ab) + (4ab+24b^2)
a(a+6b) + 4b(a+6b)
(a+4b)(a+6b)

Therefore, the original expression factors completely to (a+4b)(a+6b)
5 0
3 years ago
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