<span>42x1176
</span><span>_______
5
that is the anwser
</span>
The third term of the expansion is 6a^2b^2
<h3>How to determine the third term of the
expansion?</h3>
The binomial term is given as
(a - b)^4
The r-th term of the expansion is calculated using
r-th term = C(n, r - 1) * x^(n - r + 1) * y^(r - 1)
So, we have
3rd term = C(4, 3 - 1) * (a)^(4 - 3 + 1) * (-b)^(3-1)
Evaluate the sum and the difference
3rd term = C(4, 2) * (a)^2 * (-b)^2
Evaluate the exponents
3rd term = C(4, 2) * a^2b^2
Evaluate the combination expression
3rd term = 6 * a^2b^2
Evaluate the product
3rd term = 6a^2b^2
Hence, the third term of the expansion is 6a^2b^2
Read more about binomial expansion at
brainly.com/question/13602562
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Answer:
y=2/1x
Step-by-step explanation:
Subtract (6,8) by (1, -2)
8--2/6-1=10/5
Simply
10/5=2
Plug in
y=2x
The answers would be -8 and 18
-8×18 = -144
-8+18 = 18-8 = 10
Answer:
37 1/8
Step-by-step explanation:
The problem probably assumes direct variation
y=kx
IF so, then plug in the values and solve for k
27=k(8)
k = 27/8
y= (27/8)x. Now let x = 11
y = (27/8)11 = 27(11)/8 = 37.125 = 37 1/8
y = 37 1/8
the problem is making some assumption about the relation between x and y. The simplest assumption that's likely is direct variation, that x and y are linearly related. The graph is a straight line through the origin with slope = 27/8
