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Marianna [84]
4 years ago
12

How much candy at $1.20 a pound should be mixed with candy worth 95¢ a pound in order to obtain a mixture of 50 pounds of candy

worth a dollar a pound?

Mathematics
2 answers:
Anna35 [415]4 years ago
5 0

Answer:

10 pounds of candy worth $1.20 per pound should be mixed with 40 pounds of candy worth 95¢ per pound

Step-by-step explanation:

Let

x ----> pounds of candy worth at $1.20 a pound

y ----> pounds of candy worth at 95¢ a pound

we know that

The pounds of candy worth at $1.20 a pound plus the pounds of candy worth at 95¢ a pound must be equal to 50 pounds of candy worth a dollar a pound

so

The linear equation that represent this situation

1.20x+0.95y=50 ----> equation A

x+y=50 ----> equation B

solve the system by graphing

Remember that the solution of the system is the intersection point both graphs

using a graphing tool

The solution is the point (10,40)

see the attached figure

therefore

10 pounds of candy worth $1.20 per pound should be mixed with 40 pounds of candy worth 95¢ per pound

inn [45]4 years ago
5 0

Answer:

10 pounds of 1.20 and 40 pounds of .95

Step-by-step explanation:

you make a box solution and you do 9+10= 21 * the amout of a momand you get 10 and 40

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You are downloading songs to your MP3 player. The ratio of pop songs to rock songs is 5 : 4. You download 40 pop songs. How many
Bond [772]

Answer:

You download 32 rock songs.

Step-by-step explanation:

*im a 7th grader so dont trust me with this answer lol*

The ratio 5 : 4 can also be written as the fraction 5/4.

The ratio pop songs, 40 : rock songs, r can be written as the fraction 40/r

Set an equation:

40/r = 5/4

Cross Multiply:

5r = 160

Divide 5 from both sides:

r = 32

There you have it, the amount of rock songs downloaded! Hopefully this helps!

7 0
4 years ago
Kirk used 10.2 centimeters of tape to wrap 3 presents. How many presents did Kirk wrap if he used 23.8 centimeters of tape?
insens350 [35]

Answer:

Kirk wrapped 7 presents with those 23.8 cm of tape.

Step-by-step explanation:

Figure out the unit rate:

10.2 cm tape

-------------------

  3 presents

or

   3 presents

-----------------------

  10.2 cm tape

Multiplying this by 23.8 cm results in the number of presents Kirk wrapped with that much tape:

(3 presents)(23.8 cm tape

--------------------------------------- = 7 presents

           10.2 cm tape

Kirk wrapped 7 presents with those 23.8 cm of tape.

7 0
4 years ago
Find the values of the six trigonometric functions of theta with the given constraint.
Evgesh-ka [11]

Answer:

The six trig ratios at 3pi/2 are:

sin(3pi/2)=-1

cos(3pi/2)=0

tan(3pi/2) (undefined)

csc(3pi/2)=-1

sec(3pi/2) (undefined)

cot(3pi/2)=0

Step-by-step explanation:

If tangent is undefined then cosine would have to be 0 given that tangent is the ratio of sine to cosine.

cosine is 0 at pi/2 and 3pi/2 in the first rotation of the unit circle.

3pi/2 satisfies the given constraint.

The six trig ratios are therefore:

sin(3pi/2)=-1

cos(3pi/2)=0

tan(3pi/2)=-1/0 (undefined)

Reciprocal values:

csc(3pi/2)=-1

sec(3pi/2) undefined since cos(3pi/2)=0

cot(3pi/2)=0/-1=0

4 0
3 years ago
Read 2 more answers
727w8w7eueurururuititoy​
SSSSS [86.1K]

Answer:

ok

Step-by-step explanation:

5 0
3 years ago
Use the given data to find the equation of the regression line. Round the final values to three significant digits, if necessary
uysha [10]

Answer:

The equation of the regression line is: y=5.055 + 1.905 \cdot x

Step-by-step explanation:

We have the following data:

\begin{array}{c|cccccccccc}Productivity&23&25&28&21&21&25&26&30&34&36\\Dexterity&49&53&59&42&47&53&55&63&67&75\end{array}

We can use the Least Squares Regression to find the line of best fit for a set of paired data.

To find the line of best fit for <em>n</em> points:

Step 1: For each (x,y) point calculate x^2 and xy.

Step 2: Sum all x, y, x^2 and xy, which gives us Σx, Σy, \sum x^2 and Σxy.

Step 3: Calculate Slope b:

b &= \frac{ n \cdot \sum{XY} - \sum{X} \cdot \sum{Y}}{n \cdot \sum{X^2} - \left(\sum{X}\right)^2}

where <em>n</em> is the number of points.

Step 4: Calculate Intercept a:

a &= \frac{\sum{Y} \cdot \sum{X^2} - \sum{X} \cdot \sum{XY} }{n \cdot \sum{X^2} - \left(\sum{X}\right)^2}

Step 5: Assemble the equation of a line

y=a + b \cdot x

Following the above steps we get:

Step 1: Find x^2 and xy as it was done in the table

Step 2: Find the sum of every column:

\sum{X} = 269 ~,~ \sum{Y} = 563 ~,~ \sum{X \cdot Y} = 15596 ~,~ \sum{X^2} = 7473

Step 3: Use the following equations to find a and b:

a &= \frac{\sum{Y} \cdot \sum{X^2} - \sum{X} \cdot \sum{XY} }{n \cdot \sum{X^2} - \left(\sum{X}\right)^2} = \frac{ 563 \cdot 7473 - 269 \cdot 15596}{ 10 \cdot 7473 - 269^2} \approx 5.055

b &= \frac{ n \cdot \sum{XY} - \sum{X} \cdot \sum{Y}}{n \cdot \sum{X^2} - \left(\sum{X}\right)^2} = \frac{ 10 \cdot 15596 - 269 \cdot 563 }{ 10 \cdot 7473 - \left( 269 \right)^2} \approx 1.905\end{aligned}

Step 4: Assemble the equation of a line

y=5.055 + 1.905 \cdot x

The graph of the regression line is:

4 0
3 years ago
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