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3 years ago

727w8w7eueurururuititoy

Mathematics

1 answer:

SSSSS [86.1K]3 years ago

5 0

Answer:

Step-by-step explanation:

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30. 3 x (5 + 6) = 33<br>33. 14 - (8 - 2) - 1 =<br>36. (3 + 2) × (4 + 6) =<br>39. 6 x 4 + 5) =

Vanyuwa [196]

Answer:

39. 29

36. 50

33. 7

30. 33

Step-by-step explanation:

39. According to the Order of Operations, in this case, Subtraction & Addition are evaluated after Division & Multiplication:

$6 \times 4 + 5 = 24 + 5 = 29$

36. Evaluate everything since everything is wrapped in parentheses:

$(3 + 2) \times (4 + 6) = 5 \times 10 = 50$

33. Evaluate everything inside of parentheses FIRST:

$14 - (8 - 2) - 1 = 14 - 6 - 1 = 7$

I am joyous to assist you anytime.

7 0

4 years ago

The sum of two and the quotient of a number x and five

Burka [1]

The sum of two and the quotient of a number x and fine.

sum= +

two= 2

quotient= divide

five= 5

2+ x/5 <- should look something like this

I hope this helps!
~kaikers

3 0

3 years ago

Read 2 more answers

A university dean is interested in determining the proportion of students who receive some sort of financial aid. Rather than ex

vredina [299]

Answer:

C. One can be 95% confident that the true proportion of all students receiving financial aid is between 0.52 and 0.66

Step-by-step explanation:

Given that the confidence interval is a term that defines a range of values with the probability to contain a population value that has an actual degree of confidence.

This is represented in a situation where population means falls in between upper and lower intervals.

Hence, in this case, the correct interpretation is option C: One can be 95% confident that the true proportion of all students receiving financial aid is between 0.52 and 0.66

3 0

3 years ago

Suppose a group of 12 students consists of five freshmen and seven sophomores. How many six-student teams can be chosen that con

Tresset [83]

Answer:

350

Step-by-step explanation:

8 0

3 years ago

aalyn [17]

Answer:

The attachment shows ΔBAC ~ ΔBDA

Step-by-step explanation:

You want segment AB to be part of two similar, but not congruent, triangles. One way to do that is to make AB the hypotenuse of one triangle and the leg of another.

It is convenient to construct these triangles using point M as the arbitrary midpoint of the hypotenuse of the larger triangle. (We don't know the coordinates of M—we just know it is on the perpendicular bisector of AB.) BC is a diameter of circle M, and AD is the altitude of ΔABC.

8 0

3 years ago

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