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3 years ago

Kirk used 10.2 centimeters of tape to wrap 3 presents. How many presents did Kirk wrap if he used 23.8 centimeters of tape?

Mathematics

1 answer:

insens350 [35]3 years ago

7 0

Answer:

Kirk wrapped 7 presents with those 23.8 cm of tape.

Step-by-step explanation:

Figure out the unit rate:

10.2 cm tape

-------------------

3 presents

-----------------------

10.2 cm tape

Multiplying this by 23.8 cm results in the number of presents Kirk wrapped with that much tape:

(3 presents)(23.8 cm tape

--------------------------------------- = 7 presents

10.2 cm tape

Kirk wrapped 7 presents with those 23.8 cm of tape.

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Answer:

$\large\boxed{(2x-5)(3x^2-4x+2)=6x^3-23x^2+24x-10}$

Step-by-step explanation:

$\text{Use FOIL:}\ (a+b)(c+d)=ac+ad+bc+bd\\\\(2x-5)(3x^2-4x+2)\\\\=(2x)(3x^2)+(2x)(-4x)+(2x)(2)+(-5)(3x^2)+(-5)(-4x)+(-5)(2)\\\\=6x^3-8x^2+4x-15x^2+20x-10\\\\\text{combine like terms}\\\\=6x^3+(-8x^2-15x^2)+(4x+20x)-10\\\\=6x^3-23x^2+24x-10$

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Which equation is the BEST fit for the data in the graph

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What 2 numbers divide to get 375 while multiplying to equal 38.4?

Rus_ich [418]

Answer:

Well, 375 is a composite number.

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3 years ago

Which linear function represents the line given by the point-slope equation y + 1 = –3(x – 5)? f(x) = –3x – 6 f(x) = –3x – 4 f(x

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Answer:

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Step-by-step explanation:

we have

y+1=-3(x-5)

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Answer:

(7,4)

Step-by-step explanation:

Use the midpoint formula:

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Sub in the points

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Final answer:

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