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Nataly [62]
4 years ago
5

A 20-liter cylinder contains 4 moles of natural gas. The temperature of the cylinder is 274 K. Assuming that the gas is ideal an

d using the universal gas constant of 0.08206 L-atm/mol-K, what is the approximate pressure in the cylinder?
A.
54.8 atm
B.
112.4 atm
C.
4.5 atm
D.
22.5 atm
Reset
Chemistry
1 answer:
goldenfox [79]4 years ago
8 0
<h3>Answer:</h3>

4.5 atm

<h3>Explanation:</h3>

<u>We are given;</u>

  • Volume of the cylinder as 20 L
  • Moles of the gas as 4 moles
  • Temperature of the gas as 274 K
  • Universal gas constant as 0.08206 L-atm/mol-K

We are required to determine the pressure in the cylinder.

  • We are going to use the ideal gas equation;
  • According to the ideal gas equation;

PV = nRT

Rearranging the formula;

P = nRT ÷ V

Replacing the values of the known variables;

P = (4 mol × 0.08206 L-atm/mol-K × 274 K) ÷ 20 L

  = 4.497 atm

  = 4.50 atm

Therefore, the pressure in the cylinder is 4.5 atm

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Read 2 more answers
Consider the following isotopic abundance data for argon (Ar) and silicon (Si):
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Answer:

Explanation:

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= 35.96755 x .00337 + 37.96272 x .00063 + 39.96240 x .99600

= .12121 + .0239165 + 39.80255

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= 25.803 + 1.35320 + .929

= 28.08

b )

No of atoms of Si  in 78.2 g = 78.2 x 6.02 x 10²³ / 28.08

= 16.76 x 10²³ .

c )

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42Ar = 41.95

2 )

C₁₆H₁₅F₂N₃O₄S

Mol weight = 16 x 12 + 1 x 15 + 2 x 19 + 3 x 14 + 4 x 16 + 32

= 192 + 15 + 38 + 42 + 64+ 32

= 383

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= 1.226 x 10²⁰ molecules .

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