A 20-liter cylinder contains 4 moles of natural gas. The temperature of the cylinder is 274 K. Assuming that the gas is ideal an d using the universal gas constant of 0.08206 L-atm/mol-K, what is the approximate pressure in the cylinder? A.
54.8 atm
B.
112.4 atm
C.
4.5 atm
D.
22.5 atm
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1 answer:
<h3>
Answer: </h3>
4.5 atm
<h3>
Explanation: </h3>
<u>We are given;</u>
Volume of the cylinder as 20 L Moles of the gas as 4 moles Temperature of the gas as 274 K Universal gas constant as 0.08206 L-atm/mol-K We are required to determine the pressure in the cylinder.
We are going to use the ideal gas equation; According to the ideal gas equation; PV = nRT
Rearranging the formula;
P = nRT ÷ V
Replacing the values of the known variables;
P = (4 mol × 0.08206 L-atm/mol-K × 274 K) ÷ 20 L
= 4.497 atm
= 4.50 atm
Therefore, the pressure in the cylinder is 4.5 atm
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