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2 years ago

How many calories are required to boil 75 grams of water not in sig figs

1 answer:

3 0

Well, each ml of water requires one calorie to go up 1 degree Celsius, so this liter of water takes 1000 calories to go up 1 degree Celsius. (There are 1000 ml, each of which needs to have its temperature raised.)

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The area that includes everything between the cell membrane and the nucleus of a cell is called the ___________.

m_a_m_a [10]

The answer is C. Cytoplasm

happy to help!!

7 0

2 years ago

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Which molecule below has hydrogen bonding? Which molecule below has hydrogen bonding? H2 CH3CH2OH HCl CH4 all of the above

QveST [7]

Answer:

$CH_3CH_2OH$

Explanation:

Hydrogen bonding:-

Hydrogen bonding is a special type of the dipole-dipole interaction and it occurs between hydrogen atom that is bonded to highly electronegative atom which is either fluorine, oxygen or nitrogen atom.

Partially positive end of the hydrogen atom is attracted to partially negative end of these atoms which is present in another molecule. It is strong force of attraction between the molecules.

Thus, hydrogen must be linked to electronegative atom which is oxygen, fluorine and nitrogen which is in $CH_3CH_2OH$ and thus, it will shown hydrogen bonding.

3 0

2 years ago

What is the vitamin in an apple?

bulgar [2K]

Answer:

98 IU

Vitamin A

Explanation:

3 0

2 years ago

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A certain reaction with an activation energy of 185 kJ/mol was run at 505 K and again at 525 K . What is the ratio of f at the h

frosja888 [35]

Answer:

The ratio of f at the higher temperature to f at the lower temperature is 5.356

Explanation:

Given;

activation energy, Ea = 185 kJ/mol = 185,000 J/mol

final temperature, T₂ = 525 K

initial temperature, T₁ = 505 k

Apply Arrhenius equation;

$Log(\frac{f_2}{f_1} ) = \frac{E_a}{2.303 \times R} [\frac{1}{T_1} -\frac{1}{T_2} ]$

Where;

$\frac{f_2}{f_1}$ is the ratio of f at the higher temperature to f at the lower temperature

R is gas constant = 8.314 J/mole.K

$Log(\frac{f_2}{f_1} ) = \frac{E_a}{2.303 \times R} [\frac{1}{T_1} -\frac{1}{T_2} ]\\\\Log(\frac{f_2}{f_1} ) = \frac{185,000}{2.303 \times 8.314} [\frac{1}{505} -\frac{1}{525} ]\\\\Log(\frac{f_2}{f_1} ) = 0.7289\\\\\frac{f_2}{f_1} = 10^{0.7289}\\\\\frac{f_2}{f_1} = 5.356$

Therefore, the ratio of f at the higher temperature to f at the lower temperature is 5.356

5 0

2 years ago

In chemistry class, a student conducted an investigation on the factors that affect the solubility of copper (II) sulfate (CUSO)

beks73 [17]

Answer:

See Explanation

Explanation:

The rate of a chemical reaction depends on certain factors. Some of these factors include; surface area, temperature, nature of reactants etc.

The trial that exhibits the slowest rate of dissolution of CuSO4 crystals is trial 2 because the crystals have a small surface area since the crystals were large. Also, the solution was not agitated or stirred to increase the rate of collision between the water and the CuSO4 crystals.

Increase in temperature, agitation of the reaction solution and high surface area increases the rate of collision between the water and CuSO4 crystals leading to a faster rate of dissolution. This occurs in trial 3.

3 0

2 years ago