Question

Here we go again lol I’m a failure and a disappointment according to my mom yayy

Answer 1

Hello! Your answer is y = -7/3x + 2.

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First, find the slope of the original line. The slope can be calculated by $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$. Substitute in the points, and you get:

$\frac{3-(-3)}{13-(-1)}$

$\frac{6}{14}$

$\frac{3}{7}$

So now we get: slope = 3/7. We do not need the full equation of the first line, as a perpendicular line only requires the slope.

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Perpendicular lines all have a slope that is a negative reciprocal of another. For example, if one line's slope was 1/4, the line perpendicular to it would have a slope of -4.

The negative reciprocal of 3/7 is -7/3. Therefore, we know the slope of the line that we are looking for is -7/3. We can substitute this into y = mx + b.

y = -7/3x + b

Now, we are given a coordinate point. Substitute that in and solve.

-5 = -7/3 * 3 + b

-5 = -7 + b

b = 2

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Therefore, the final equation we are looking for is y = -7/3x + 2.

Hope this helps!