To be honest I am not sure but maybe 32 because that is half or 96 but I was never really good with scales.
The bearing of the individuals from each other are as indicated below;
- S45°E
- N25°E
- S65°E
- S15°E
- N45°E
- N75°E
<h3>What is bearing of Henley from Dinder?</h3>
It follows from the task content that the bearing of the individuals from each other are expected to be determined.
a) For Henley from Dinder; it follows from observation that Henley is; S45°E of Dinder's position.
b) For Dinder from Weare; it follows from observation that Dinder is; N25°E of Weare's position.
c) For Weare from Dinder; it follows from observation that Weare is; S65°E of Dinder's position.
d) For Weare from Henly; it follows from observation that Weare is; S15°E of Dinder's position.
e) For Dinder from Henly; it follows from observation that Dinder is; N45°E of Henly's position.
f) For Henly from Weare; it follows from observation that Henly is; N75°E of Weare's position.
Read more on bearing;
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We are asked for the total or three card hands that can be made with two aces. The three-card hand should have two aces. We will use permutation in solving this problem and the solution is shown below:
nPr = n! /(n-r)!
n=3
r=2
3P2 = 3!/(3-2)!
3P2 = 6
The answer is 6.
Answer:
26.6 m
Step-by-step explanation:
Given the figures are similar
linear ratio = a : b
area ratio = a² : b²
here
area ratio = 16 : 25, then
linear ratio = 4 : 5 ( square root of both area ratio parts )
let the perimeter of the larger figure be x, then by proportion
= 
( cross- multiply )
4x = 106.5 ( divide both sides by 4 )
x ≈ 26.6
Hence perimeter of larger figure is approximately 26.6 m
