What is the area of the triangle enclosed by the lines y=0,x=8 and y =x?
1 answer:
Since we have a horizontal line, y=0 on the x-axis, a vertical line at x=8, and a 45 degree angle line from y=x.
So you essentially have a right triangle with a base that is 8 units wide, and a side that is 8 units high.
Since the area is bh/2, A=8*8/2=32u^2
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