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Viefleur [7K]
3 years ago
14

What is the area of the triangle enclosed by the lines y=0,x=8 and y =x?

Mathematics
1 answer:
Alinara [238K]3 years ago
7 0
Since we have a horizontal line, y=0 on the x-axis, a vertical line at x=8, and a 45 degree angle line from y=x.

So you essentially have a right triangle with a base that is 8 units wide, and a side that is 8 units high.

Since the area is bh/2, A=8*8/2=32u^2
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The base of a square measures 7 cm, and its height measures 6 centimeters. How tall is your area?
Alexxandr [17]

Answer:

42cm^{2}

Step-by-step explanation:

In order to find the area of a square you take the base and multiply it by the height.

Base x Height = Area

In this case you have 7cm as the base and 6cm as the height.

All you have to do after that is multiply the two together.

Make sure that you remember to put the unit (cm) and make sure that it is cm^{2} because some teachers are uptight about that stuff.

Hope this helped!

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5 0
3 years ago
A quadrilateral has angles that measure 74°, 93°, and 117°.
Lana71 [14]

Answer:

D

Step-by-step explanation:

74 + 93 + 117= 284

360 - 284 = 76

3 0
3 years ago
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mote1985 [20]

Answer:

B

Step-by-step explanation:

I think your supposed to just count the dots

6 0
2 years ago
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6. Find JL.<br> Please and thank you. 5x-16=3x+4
IRINA_888 [86]

Answer:

JL = 68

Step-by-step explanation:

JM = ML

Hence, 3x + 4 = 5x - 16

Subtract 3x from both sides

4 = 2x - 16

Add 16 to both sides

20 = 2x

Divide both sides by 2

10 = x

Now we want to find JL

Note that JL = JM + ML

JM = 3x + 4 and x = 10

Substitute 10 for x

3(10) + 4

Multiply

30 + 4

Add

JM = 34

Because JM = ML

We simply multiply 34 times 2 to find the length of JL

34 * 2 = 68

JL = 68

4 0
2 years ago
Can you find 10/21 of 3/ 10
hoa [83]
<span>0.1428571428 would be the correct answer</span>
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3 years ago
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