(2r+y+3z=13 1+2y = 11 3r+z=10

The annual health insurance premium for Ms Everett is $12,304. her employer pays 70% of the premium and deducts the remainder fr

Gekata [30.6K]

Answer: See each one below:

1) Since she is paying for 30% of the cost, we multiply it by 0.3. Then, since it is over the whole year, we divide it by 12.

12304 * 0.3 / 12 = 307.6 B

2) First, we subtract the cost of the 50 deductible, then multiply the amound by 0.2 because he has to pay 20% of the balance.
1060 - 50 = 1010 x 0.2 = 202 A

3) First, we find the total cost of the visits. Mattie has to pay for 40% so times it by 0.4. Then, don't forget to add in the cost of 12 co-pays of $15 each.
3660 * 0.4 = 1464 + 15(12) = 1664 B

7 0

3 years ago

Read 2 more answers

16-2v+3 what is the answer pls help

djyliett [7]

Answer:

the answer is 19-2v combine like terms if not that then try this....

19-2y=0

-2y=-19

Then divide by -2

y=-19/-2

=9.5

4 0

3 years ago

1.Use Euler’s Formula to find the missing number. Edges: 40

PtichkaEL [24]

Answer:

Euler's Formula states that:

V -E +F = 2 meaning that the vertices minus the edges plus the faces of a convex polyhedron will always equal two.

So, for the initial question, we have 40 edges and 24 faces.

So, vertices = 2 + Edges -Faces

Vertices = 2 + 40 - 24

Vertices = 18

Source: https://www.1728.org/platonic.htm

Step-by-step explanation:

6 0

3 years ago

3.

Vitek1552 [10]

To solve this we are going to use the future value of annuity due formula: $FV=(1+ \frac{r}{n} )*P[ \frac{(1+ \frac{r}{n})^{kt}-1 }{ \frac{r}{n} } ]$
where
$FV$ is the future value
$P$ is the periodic deposit
$r$ is the interest rate in decimal form
$n$ is the number of times the interest is compounded per year
$k$ is the number of deposits per year

We know for our problem that $P=420$ and $t=15$ . To convert the interest rate to decimal form, we are going to divide the rate by 100%: $r= \frac{10}{100} =0.1$ . Since Ruben makes the deposits every 6 months, $k=2$ . The interest is compounded semiannually, so 2 times per year; therefore, $k=2$ .
Lets replace the values in our formula:

$FV=(1+ \frac{r}{n} )*P[ \frac{(1+ \frac{r}{n})^{kt}-1 }{ \frac{r}{n} } ]$
$FV=(1+ \frac{0.1}{2} )*420[ \frac{(1+ \frac{0.1}{2})^{(2)(15)}-1 }{ \frac{01}{2} } ]$
$FV=29299.53$

We can conclude that the correct answer is $29,299.53

8 0

3 years ago

After a 15% increase, a town has 115 people. What was the population before the increase?

Arte-miy333 [17]

Answer:

100 people

Step-by-step explanation:

Population Of People=115Percentagencrease=15%

The New Population corresponds to 115%

(That is 100+15)

We want to find the population that corresponds to 100% that is the original population.

Therefore Original Population;

 $\frac{100}{115}\times {115}{}$ 

 $100 \: people$ 

7 0

3 years ago