Ask question

Ask question

All categories

3 years ago

11

How to turn 20/10 into a mixed number

2 answers:

allochka39001 [22]3 years ago

7 0

How you turn 20/10 into a mixed number is you see what the denominator can go into the numerator and in this case it would be 10 and so you see how many times 10 can go into 20 without going over and in this case it would be 2 so the answer would be 2.

Lady_Fox [76]3 years ago

3 0

$\frac{20}{10}$ cannot be changed to a mixed number. 10 could divide both numerator and denominator. And you get 2.

You might be interested in

Which of the following are ordered pairs for the equation y = 1/8x + 11

Anna11 [10]

Answer:

(0, 11) is a solution.

(8, 12) is a solution.

(16, 13) is a solution

(1, 89/8)

(2, 45/4)

Step-by-step explanation:

y = 1/8x + 11

for this equation....

y = (1/8) x + 11

let x = 0 get

y = 0 + 11 = 11

(0, 11) is a solution.

(8, 12) is a solution.

(16, 13) is a solution

(1, 89/8) because y = 1/8 + 11 = 1/8 + 88/8 = 89/8

(2, 45/4)

3 0

2 years ago

Simplify the monomials

Zielflug [23.3K]

Answer:

$(4a)^{-3}*^{-4}$

$x^m*x^n=x^{m+n}$

$(4a)^{-3}*a^{-4}$

$(-4)^{-3}\: a^{-3}*a^{-4}$

$4^{-3}\:a^{-3-4}$

$\cfrac{1}{4^3} \:a^{-7}$

$\boxed{\frac{1}{64a^{7}} }$

~

$(3xy)^2*(-4x^3y^2)^3$

$9x^2y^2*(64x^9y^6)$

$\boxed{-576x^{11}y^8}$

~

$(4a^{-1}b^5c^{-3})^3$

$(4)^3(a^{-1})^3(b^5)^3(c^{-3})^3$

$(4*4*4)\:a^{-1*3}\:b^{5*3}\:c^{-3*3}$

$64\:a^{-3}b^{15}c^{-9}$

$\boxed{\frac{64b^{15}}{a^3c^9}}$

7 0

2 years ago

PLZ HELPPPPP!!!!!!!!!!!!!!

disa [49]

A. or "Company A"

The reason is because its the biggest and longest box on the table

7 0

3 years ago

Please Help! <br> What is 40 divided by 940?<br> 23.5<br> 34<br> 67<br> 13.9<br> Please help!!

miv72 [106K]

Answer:

It's 23.5

Step-by-step explanation:

940/40 = 23.5

5 0

3 years ago

Read 2 more answers

If f(x)=3x+10x and g(x)=4x-2 find (f+g)(x)<br> A:3x+6x+2<br> B:17x-2<br> C:3x+14x-2<br> D:3x-6x+2

Rudik [331]

Answer:

3x^2+14x-2 if you meant f(x)=3x^2+10x and g(x)=4x-2

and I think C was meant to read 3x^2+14x-2

Please correct me if I have mistranslated. Thank you kindly.

Step-by-step explanation:

I kind of wonder if you meant f(x)=3x^2+10x and g(x)=4x-2.

(f+g)(x)=f(x)+g(x)

=(3x^2+10x)+(4x-2)

=3x^2+10x+4x-2

=3x^2+(10x+4x)-2 I paired 10x and 4x together because they are like terms

=3x^2+14x-2

7 0

2 years ago