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Fofino [41]
3 years ago
11

How to turn 20/10 into a mixed number

Mathematics
2 answers:
allochka39001 [22]3 years ago
7 0
How you turn 20/10 into a mixed number is you see what the denominator can go into the numerator and in this case it would be 10 and so you see how many times 10 can go into 20 without going over and in this case it would be 2 so the answer would be 2.
Lady_Fox [76]3 years ago
3 0
\frac{20}{10} cannot be changed to a mixed number. 10 could divide both numerator and denominator. And you get 2.
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Differentiate y=x⁴(1-2x⁵)⁶(5-8x³)².​
Liula [17]

Step-by-step explanation:

Let y(x)=f(x)g(x)h(x) where

f(x) = x^4

g(x)= (1 -2x^5)^6

h(x)= (5 - 8x^3)^2

so that

y(x) = x^4(1 -2x^5)^6(5 - 8x^3)^2

Recall that the derivative of the product of functions is

y'(x)=f'(x)g(x)h(x)+f(x)g'(x)h(x)+f(x)g(x)h'(x)

so taking the derivatives of the individual functions, we get

f'(x) = 4x^3

g'(x) = 6(1 - 2x^5)^5(-10x^4)

h'(x) = 2(5 - 8x^3)(-24x^2)

So the derivative of y(x) is given by

y'(x) = 4x^3(1 -2x^5)^6(5 - 8x^3)^2 +  x^4 6(1 -2x^5)^5(-10x^4)(5 - 8x^3)^2 +  x^4(1 -2x^5)^6 2(5 - 8x^3)(-24x^2)

or

y'(x) = 4x^3(1 -2x^5)^6(5 - 8x^3)^2

\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:- 60x^8(1 -2x^5)^5(5 - 8x^3)^2

\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:- 48x^6(1 -2x^5)^6 2(5 - 8x^3)

3 0
2 years ago
I need help with the question below
Butoxors [25]

Answer:

a: 1/12

b: 1/6

c: 1/2

d: 1/2

e: 1/12

f: 1/3

Step-by-step explanation:

3 0
3 years ago
The perimeter of a rectangular field is 60 meters. Its area is 200 square meters. Find its dimensions.
Vanyuwa [196]

Answer:

20 m by 10 m

Step-by-step explanation:

let w be width and l be length , then

2(l + w) = 60 ( divide both sides by 2 )

l + w = 30 ( subtract w from both sides )

l = 30 - w → (1)

lw = 200 → (2)

Substitute l = 30 - w into (2)

w(30 - w) = 200 ← distribute parenthesis on left side

30w - w² = 200 ( subtract 200 from both sides )

30w - w² - 200 = 0 ( multiply through by - 1 )

w² - 30w + 200 = 0 ← in standard form

(w - 10)(w - 20) = 0 ← in factored form

Equate each factor to zero and solve for w

w - 10 = 0 ⇒ w = 10

w - 20 = 0 ⇒ w = 20

Substitute these values into (1)

l = 30 - 10 = 20

l = 30 - 20 = 10

dimensions of field is 20 m by 10 m

4 0
2 years ago
Read 2 more answers
PLZ HURRY!!!!!!!!!!!!!<br> Simplify. <br> −4x^2(5x^4−3x^2+x−2)
Simora [160]

\bold{Answer}

\boxed{\bold{-20x^6+12x^4-4x^3+8x^2}}

\bold{Explanation}

  • \bold{Simplify: \ -4x^2\left(5x^4-3x^2+x-2\right)}

\bold{------------------}

  • \bold{Distribute \ Parenthesis}

\bold{\left(-4x^2\right)\cdot \:5x^4+\left(-4x^2\right)\left(-3x^2\right)+\left(-4x^2\right)x+\left(-4x^2\right)\left(-2\right)}

  • \bold{Apply \ Addition \ / \ Subtraction \ Rules: \ +\left(-a\right)=-a,\:\:\left(-a\right)\left(-b\right)=ab}

\bold{-4\cdot \:5x^4x^2+4\cdot \:3x^2x^2-4x^2x+4\cdot \:2x^2}

  • \bold{Simplify \ -4\cdot \:5x^4x^2+4\cdot \:3x^2x^2-4x^2x+4\cdot \:2x^2: \ -20x^6+12x^4-4x^3+8x^2}

\bold{-20x^6+12x^4-4x^3+8x^2}

\boxed{\bold{Eclipsed}}

5 0
3 years ago
The function of f(x) = 3x + 2 has a domain of -3 &lt; x &lt; 5. What is the domain of f-1(x)?
Flura [38]
<h3>Answer:    -7 < x < 17</h3>

====================================================

Explanation:

Plug in the lower bound of the domain, which is x = -3

f(x) = 3x+2

f(-3) = 3(-3)+2

f(-3) = -9+2

f(-3) = -7

If x = -3, then the output is y = -7. Since f(x) is an increasing function (due to the positive slope), we know that y = -7 is the lower bound of the range.

If you plugged in x = 5, you should find that f(5) = 17 making this the upper bound of the range.

The range of f(x) is -7 < y < 17

Recall that the domain and range swap places when going from the original function f(x) to the inverse f^{-1}(x)

This swap happens because how x and y change places when determining the inverse itself. In other words, you go from y = 3x+2 to x = 3y+2. Solving for y gets us y = (x-2)/3 which is the inverse.

-----------------------

In short, we found the range of f(x) is -7 < y < 17.

That means the domain of the inverse is -7 < x < 17 since the domain and range swap roles when going from original to inverse.

6 0
3 years ago
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