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Fofino [41]
3 years ago
11

How to turn 20/10 into a mixed number

Mathematics
2 answers:
allochka39001 [22]3 years ago
7 0
How you turn 20/10 into a mixed number is you see what the denominator can go into the numerator and in this case it would be 10 and so you see how many times 10 can go into 20 without going over and in this case it would be 2 so the answer would be 2.
Lady_Fox [76]3 years ago
3 0
\frac{20}{10} cannot be changed to a mixed number. 10 could divide both numerator and denominator. And you get 2.
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Firlakuza [10]
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There are many system of inequalities that can be created such that only contain points C and F in the overlapping shaded regions.

Any system of inequalities which is satisfied by (2, 2) and (3, 4) but is not stisfied by <span>(-3, -4), (-4, 3), (1, -2) and (5, -4) can serve.

An example of such system of equation is
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The system of equation above represent all the points in the first quadrant of the coordinate system.
The area above the x-axis and to the right of the y-axis is shaded.



Part 2:
It can be verified that points C and F are solutions to the system of inequalities above by substituting the coordinates of points C and F into the system of equations and see whether they are true.

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Given that </span><span>Natalie can only attend a school in her designated zone and that Natalie's zone is defined by y < −2x + 2.

To identify the schools that Natalie is allowed to attend, we substitute the coordinates of the points A to F into the inequality defining Natalie's zone.

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For point C(2, 2): 2 < -2(2) + 2; 2 < -4 + 2; 2 < -2 which is false

For point D(1, -2): -2 < -2(1) + 2; -2 < -2 + 2; -2 < 0 which is true

For point E(5, -4): -4 < -2(5) + 2; -4 < -10 + 2; -4 < -8 which is false

For point F(3, 4): 4 < -2(3) + 2; 4 < -6 + 2; 4 < -4 which is false

Therefore, the schools that Natalie is allowed to attend are the schools at point A, B and D.
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Answer:

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