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Phantasy [73]
3 years ago
14

Timothy read 3,876 pages this school year. Amelia read 3,768 pages. Who read more pages this school year? E​

Mathematics
1 answer:
12345 [234]3 years ago
8 0

Answer:

Timothy

Step-by-step explanation:

Timothy because he read 3,876 pages this year.

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In the problem, 2x4 - 3x3 - 6x2 + 11x +8 divided by (x - 2), what is the remainder?
Jet001 [13]

remainder = 14

2x^{4} - 3x^{3} - 6x² + 11x + 8

= 2x³ + x² - 4x + 3 + \frac{14}{x - 2}


8 0
3 years ago
I need help asap I’m overtime
solong [7]

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4 0
3 years ago
Working as an insurance salesperson, Ilya earns a base salary and a commission on each new policy, so Ilya’s weekly income, II,
Morgarella [4.7K]

Answer:

l(n) = 80n + 520

Step-by-step explanation:

From the information given in the  question, there is a relationship between the number of new policy sold, n, and earning, I

           For 3 new policies, he earned $760

           For 5 new policies, he earned $920.

The rate of change of IIya's earning with respect to number of new policy sales is

             m = \frac{dI}{dn}

             m = \frac{920 - 760}{5 - 3}

             m = $160 / 2 policies

             m = $80 / policy

The linear equation for the relationship is;

             l(n) = mn + b

I(n) is Ilya’s weekly income which is a function of the number of new policies, n

m is the rate of change of I with respect to n

n is the number of new policies,

b is the intial function which is IIya's income when n equals zero

Recall, Ilya earns a commission of $80 for each policy sold during the week. (m = $80 per policy)

                 l(n) = 80n + b

To complete the relationship l, we need to calculate the initial value b.

For 3 new policies, he earned $760,

             760 = 80(3) + b

             760 = 240 + b

             b = 760 - 520

             b = 520

The final equation is l(n) = 80n + 520

From the final equation, we can deduce that Ilya’s weekly salary is $520 and he earns an additional $80 commission for each new policy sold.

6 0
3 years ago
Quadrilateral LMNO has diagonals that intersect at point P. If LP=NP, MP = y + 25, and OP = 5y + 29, find the length of MO such
salantis [7]
The right  answer will be  c.61 that is your answer
8 0
3 years ago
Read 2 more answers
The perimeter of a rhombus is 560 meters and one of its diagonals has a length of 76 meters. Find the area of the rhombus.
borishaifa [10]
The perimeter is the sum of the side lengths of a shape. <span> A </span>diagonal is a line segment joining two vertices of a polygon or polyhedron <span>when those vertices are not on the same edge. We calculate as follows:

Perimeter = 4a
560 = 4a
a = 140 meters

</span>A=(1/2)d√(4a^2 - d^2)
A = 10240.56 m^2
4 0
3 years ago
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