(7z^3+42z^2-15z+1)- (36z^2+12z-21)

Mathematics

2 answers:

My name is Ann [436]3 years ago

6 0

Answer:

7z^3+6z^2-27z+22

Step-by-step explanation:

The given question is of subtraction:

So,

(7z^3+42z^2-15z+1)- (36z^2+12z-21)

=7z^3+42z^2-15z+1-36z^2-12z+21

Combining alike terms to simplify

=7z^3+42z^2-36z^2-15z-12z+1+21

=7z^3+6z^2-27z+22

So the answer in simplified form is:

7z^3+6z^2-27z+22 ..

zalisa [80]3 years ago

4 0

Answer:

7z³ + 6z² - 27z + 22

Step-by-step explanation:

It is given an expression in variable z,

(7z³ + 42z² - 15z + 1) - (36z² + 12z - 21)

<u>To find the simplified form</u>

(7z³ + 42z² - 15z + 1) - (36z² + 12z - 21)

= (7z³ + 42z² - 15z + 1 - 36z² - 12z + 21)

= 7z³ + 42z² - 36z² - 15z -12z + 1 + 21

= 7z³ + 6z² - 27z + 22

Therefore the simplified expression is = 7z³ + 6z² - 27z + 22

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Consider a normal distribution curve where the middle 85 % of the area under the curve lies above the interval ( 8 , 14 ). Use t

NeTakaya

Answer:

$\mu = 11$

$\sigma = 2.08$

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Middle 85%.

Values of X when Z has a pvalue of 0.5 - 0.85/2 = 0.075 to 0.5 + 0.85/2 = 0.925

Above the interval (8,14)

This means that when Z has a pvalue of 0.075, X = 8. So when $Z = -1.44, X = 8$ . So