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kotegsom [21]
3 years ago
6

Which expression is equvialent to this expression 3/4 (4h -6 )

Mathematics
1 answer:
Gekata [30.6K]3 years ago
4 0

Answer:

are there choices?

Step-by-step explanation:

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The half-life of a drug in the blood is 2 hours. Assume that a person starts with 0.6 mg of the drug in their system. Fill in th
sleet_krkn [62]
<span>If the half-life of the drug is 2 hours, then in 2 hours 0.6 mg of the drug becomes 0.3 mg. In two more hours (4 hours total) it is 0.15 mg, 2 more hours (6 hours) .075 mg. In two more hours (8 hours) it is .0375 mg, rounded to 0.04. The answer is 8 hours.</span>
3 0
3 years ago
Kiara has a ribbon that measures 1/4 of an inch and Jillian has a ribbon that measures 2/3 of an inch. Jillian says their ribbon
fenix001 [56]

Answer:

Jillian is Incorrect as fraction can never be balanced based on numerator or denominator.

Step-by-step explanation:

Given:

Measure of ribbon Kiara has = \frac{1}{4} \ inch

Measure of ribbon Jillian has = \frac{2}{3} \ inch

Now given:

Jillian says their ribbons are equal in length because her numerator is one more than kiara's and her denominator is one less, therefore balancing the two fractions.

we need to find whether statement is correct or not.

First we will find the decimal value of the given fraction's

\frac{1}{4} \ inch can rewritten as 0.25\ inch

Measure of ribbon Kiara has = 0.25 inch

\frac{2}{3} \ inch can be Rewritten as 0.67\ inch

Measure of  ribbon Jillian has = 0.67 inch

Now we can see that;

0.67 inch is greater than 0.25 inch.

Hence we can say that ribbons are not in equal length.

Also the fraction can never be balanced by decreasing or increasing the numerator or denominator.

7 0
4 years ago
What is the range of ƒ(x) = |x|?<br><br> (–∞, 0)<br> (–∞, ∞)<br> (0, ∞)<br> [0, ∞)
larisa86 [58]

The range of the function f(x) = |x| is [0,∞)

<h3>How to determine the range?</h3>

The function is given as:

f(x) = |x|

The above is the parent equation of an absolute value function.

The above function cannot output any negative value.

This means that:

ƒ(x) >= 0

As an interval notation, we have:

[0,∞)

Hence, the range of the function f(x) = |x| is [0,∞)

Read more about range at:

brainly.com/question/10197594

#SPJ1

6 0
2 years ago
A truck's varying distance from the warehouse, d , measured in miles is modeled by the formula d=t2+50t where t is the varying n
Dafna1 [17]

Answer:

  • 7.596 hours
  • 57.596 mph

Step-by-step explanation:

a) The distance is given as ...

  d = t^2 +50t

We want to find the value of t for which this distance is 437.5 miles. That means we want to solve the equation ...

  437.7 = t^2 +50t

We can complete the square by adding the square of half the t coefficient, (50/2)^2 = 625

  437.5 +625 = t^2 +50t +625

  1062.5 = (t +25)^2

  √1062.5 -25 = t ≈ 7.596 . . . . hours

It will take the truck about 7.596 hours to reach its destination.

__

b) Average speed is total distance divided by total time. Here, we can find the average speed as ...

  d/t = (t^2 +50t)/t = t +50

That is, the average speed over the 437.5-mile trip is ...

  7.596 +50 = 57.596 . . . . miles per hour

The car must maintain a constant speed of 57.596 mph to reach the destination at the same time.

_____

When solving equations using a graphing calculator, I like to put them into a form such that the solution is the x-intercept. Here, that means the equation we're solving is ...

  x^2 +50x -437.5 = 0 . . . . x is hours to destination

8 0
3 years ago
Using the following equation, find the center and radius of the circle. You must show all work and calculations to receive credi
adoni [48]

Answer:

r = 4

The center is:

(2, -4)

Step-by-step explanation:

We have the following equation

x^2 - 4x + y^2 + 8y = -4

The general equation of a circle has the following form

(x-h)^2 + (y-k)^2 = r^2

Where r is the radius and the point (h, k) is the center of the circle

To transform the given equation in the general equation of a circumference we must use the method of square completions

Step 1

(x^2 - 4x) + (y^2 + 8y) = -4

<u>Step 2</u>

<u> </u>Add and subtract (\frac{b}{2})^2 For an equation of the form

ax^2 +bx +c

(x^2 - 4x +4)-4 + (y^2 + 8y +16) -16= -4

<u>Step 3  </u> Factor the expressions within the parentheses

(x-2)^2-4 + (y+4)^2 -16= -4

<u>Step 4 Simplify</u>

(x-2)^2 + (y+4)^2= -4+16+4

(x-2)^2 + (y+4)^2= 4^2

Finally

r = 4

The center is:

(2, -4)

7 0
3 years ago
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