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3 years ago

The solution of these problem

Mathematics

1 answer:

Shtirlitz [24]3 years ago

6 0

Answer:

You can put AFE or BFC

Step-by-step explanation:

Supplementary angles are angles that add up to 180 degrees

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What is 126 billion divied by 108.2 billion

LUCKY_DIMON [66]

the answer is 0.00116451016

hope it helped :)

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3 years ago

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Which expression is equivalent to -3(4x-0.50)? PLEASEEEEEEEEEEEEE HELPPP

Misha Larkins [42]

Final Answer: $-12x + 1.5$

Steps/Reasons/Explanation:

Question: Which expression is equivalent to $-3(4x - 0.50)?$

Step 1: Expand by distributing terms.

$-3$ × $4x - 3$ × $-0.50$

Step 2: Simplify $-3$ × $4x$ to $-12x$ .

$-12x - 3$ × $-0.50$

Step 3: Simplify $3$ × $-0.50$ to $-1.5$ .

$-12x - (-1.5)$

Step 4: Remove parentheses and add.

$-12x + 1.5$

~I hope I helped you :)~

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3 years ago

What numbers less than 200 are divisble by 4 but not 12

kolezko [41]

Answer:

There are 48 numbers that satisfy the condition

Step-by-step explanation:

Find the relationship between 3 and 12

3 * 4 = 12

The maximum number of multiples of 12 within 200 is 18.

The maximum number of multiples within 200 is 66.

So the number of numbers within 200 that go exactly into 3 but not exactly into 12 is:

66-18 = 48

3 0

2 years ago

The height of a sunflower plant varies directly with it's age.Once it has sprouted from the ground,when a sunflower is 2 week ol

yKpoI14uk [10]

(38/2) x 3 1/2 or (114/6) x 3 1/2=66.5

so your answer is 66.5

7 0

3 years ago

Two fair dice, one blue and one red, are tossed, and the up face on each die is recorded. Define the following events:

ZanzabumX [31]

Answer:

Step-by-step explanation:

Given that two fair dice, one blue and one red, are tossed, and the up face on each die is recorded.

a) P(E) = P(the difference of the numbers is 3 or more}

Favourable events are (1,4) (1,5)(1,6) (2,5) (2,6) (3,6) (4,1) (5,1) (5,2) (6,1) (6,2)(6,3)

P(E) = $\frac{12}{36} =\frac{1}{3}$

b)P(F)

Favourable events for F = (1,1) (2,2)...(6,6)

P(F) = $\frac{6}{36} =\frac{1}{6}$

c) P(EF)

There is no common element between E and F

P(EF) =0

4 0

3 years ago

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