We are given :
![\sqrt{4x^{2}-20x+25}](https://tex.z-dn.net/?f=%20%5Csqrt%7B4x%5E%7B2%7D-20x%2B25%7D%20%20%20)
Step 1: factor the part inside square root
The function given inside square root is of quadratic form.
So let us try to factorise it using AC method.
Here A*C = 4*25 = 100
so we have to find factors of 100 that add up to give -20.
the two factors are -10 and -10.
Rewriting the function :
![4x^{2} -20x+25](https://tex.z-dn.net/?f=%204x%5E%7B2%7D%20-20x%2B25%20)
=![4x^{2} -10x-10x+25](https://tex.z-dn.net/?f=%204x%5E%7B2%7D%20-10x-10x%2B25%20)
=![2x(2x-5) - 5(2x-5)](https://tex.z-dn.net/?f=%202x%282x-5%29%20-%205%282x-5%29%20)
=![(2x-5)^{2}](https://tex.z-dn.net/?f=%20%282x-5%29%5E%7B2%7D%20%20)
Step 2:
Now we take square root of the factorised form
![\sqrt{(2x-5)^2}](https://tex.z-dn.net/?f=%20%5Csqrt%7B%282x-5%29%5E2%7D%20%20)
= ![2x-5](https://tex.z-dn.net/?f=%202x-5%20)
Answer : (2x-5)
Answer: Hello your question is incomplete attached below is the missing
n ( 1 + n )
Step-by-step explanation:
P( Bob hits target ) = 1/3
P( Eve hits target ) = 2/3
P( Carol hits target ) = 1
<u>Compute the P that Bob wins in a duel against Eve alone</u>
P(Bob hits the target in first shot ) = n = 1/3
P(Bob hits the target in second shot ) = n^2 = ( 1/3 * 1/3 ) = 1/9
hence the probability of Bob winning( i.e. P( Bob wins Event E1 ) = n + n^2 = n ( 1 + n )
Answer:
X = 9, -1
Step-by-step explanation:
1, Factor it
(x-9) (x+1) = 0
2. Both of a factor will = 0
x-9 = 0
x+1=0
3. Solve
x=9
x=1
Answer:
x = 10
Step-by-step explanation:
Since both equations give y in terms of x, equate the right sides
3x - 28 = - 2x + 22 ( add 2x to both sides )
5x - 28 = 22 ( add 28 to both sides )
5x = 50 ( divide both sides by 5 )
x = 10