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Vlada [557]
3 years ago
10

Please help answer the two questions

Mathematics
1 answer:
marin [14]3 years ago
5 0

Answer:

1. C (q³)

2. A (12kr (to the 7th power)

Step-by-step explanation:

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HELP ME PLEASEEEEEEE
scoray [572]

Answer:

It would be in this order:

Types of Quads:

Rectangle

Square

Rhombus

Trapezoid

Type of Triangles:

Equaliteral

Isoceles

Scalene

Step-by-step explanation:

Hope it helps

6 0
2 years ago
Find the result of 765 times 95 divided by 5?<br><br>please help me ​
Marizza181 [45]

Answer:

14,535

Step-by-step explanation:

765 times 95 : 765 x 95 = 72,675

divided by 5 : \frac{ 72,675}{5} = 14,535

Let me know if you want an even more in-depth answer

Happy to do so !

7 0
2 years ago
Help me please for brainlist
allochka39001 [22]

Answer:

b. 82m³

Step-by-step explanation:

V = \frac{1}{3}(\frac{1}{2} bh_1)h_2\\b = 8.2m\\h_1 =  4m\\h_2 = 15m\\\\V = \frac{1}{3}(\frac{1}{2}(8.2)(4))(15)\\V = 82m^{3}\\

3 0
2 years ago
Read 2 more answers
Identify each function that has a remainder of -3 when divided x+6
Sergeu [11.5K]

Answer:

D

Step-by-step explanation:

According to remainder theorem, you can know the remainder of these polynomials if you plug in x = -6 into them.

<em>So we will plug in -6 into x of all the polynomials ( A through D) and see which one equals -3.</em>

<em />

<em>For A:</em>

x^5 + 2x^2 - 30x + 30\\=(-6)^5 + 2(-6)^2 - 30(-6) + 30\\=-7494

For B:

x^4 + 4x^3 - 21x^2 - 53x + 12\\=(-6)^4 + 4(-6)^3 - 21(-6)^2 - 53(-6) + 12\\=6

For C:

x^3 - 10x^2 - 7\\=(-6)^3 - 10(-6)^2 - 7\\=-583

For D:

x^4 + 6x^3 - 10x - 63\\=(-6)^4 + 6(-6)^3 - 10(-6) - 63\\=-3

The only function that has a remainder of -3 when divided by x + 6 is the fourth one, answer choice D.

5 0
3 years ago
LaToya had a large collection of basketball cards. She decided to give half of them to her friends, Aaron, and a fourth of them
Savatey [412]
1-1/2-1/4=1/4  If 75 is 1/4, then just divide to get the whole thing.  75/1/4=200
She had two hundred cards to start with.  Hope this helps!!!
5 0
3 years ago
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