Question

A box is tossed upward from a building that is 18 meters high, at a speed of 9 meters per second. What is the height of the box at 1 second if the height is given in meters by h(t)=−4.9t^2+9t+18 where t is seconds?

Answer 1

Answer:

22.1 meters

Step-by-step explanation:

The equation for the height of the box is given  by:

$h(t)=-4.9t^2+9t+18$ where t is time in seconds.

After 1 second,

The height of the box

$h(1)=-4.9(1)^2+9(1)+18\\=-4.9+9+18\\=22.1 \:meters$

Answer 2

Answer:

22.1 meters

Step-by-step explanation:

To calculate the height of the box at 1 second after it was tossed upward, we just need to use the equation of the height that the question gave us - h(t) - using the time t = 1:

h(t) = -4.9*t^2 + 9*t + 18

h(1) = -4.9*1^2 + 9*1 + 18

h(1) = -4.9 + 9 + 18 = 22.1 meters

The height of the box at 1 second is 22.1 meters.