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2 years ago

Write .0085 in scientific notation

Mathematics

2 answers:

nikitadnepr [17]2 years ago

8 0

Answer:

8.5 * 10^-3

Step-by-step explanation:

Nookie1986 [14]2 years ago

7 0

$8.5 \times {10}^{ - 3?}$

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Peggy had three times as many quarters as nickels. She had $1.60 in all. How many nickels and how many quarters did she have?. .

Andru [333]

Let

n-------> the number of nickels

q------> the number of quarters

we know that

$1\ quarter=\$0.25\\1\ nickel=\$0.05$

$0.05n+0.25q=1.60$ ----> equation A

$q=3n$ ----> equation B

substitute equation B in equation A

$0.05n+0.25[3n]=1.60$

$0.05n+0.75n=1.60$

$0.80n=1.60$

$n=2$

Find the value of q

$q=3*2=6$

therefore

<u>The answer part a) is</u>

the number of nickels are $2$ and the number of quarters are $6$

<u>the answer Part b) is</u>

The expressions that represents the number of quarters is

$q=3n$

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2 years ago

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MAVERICK [17]

Answer:

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2 years ago

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Can someone help me with the areas?

9966 [12]

Answer:

for 1. it is 99 and for 3. it is 343.75

Step-by-step explanation:

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1 year ago

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Carly's family traveled 3/10 of the distance to her grandmother's house on Saturday. They traveled 3/7 of the remaining distance

polet [3.4K]

Answer:

3/10 of the total distance to her grandmother's house was traveled on Sunday

Step-by-step explanation:

Carly's family traveled distance of Saturday = $\frac{3}{10}$

Remaining distance = $1-\frac{3}{10}=\frac{7}{10}$

They traveled 3/7 of the remaining distance on Sunday.

So, Distance traveled on Sunday = $\frac{3}{7}(\frac{7}{10})$

Distance traveled on Sunday = $\frac{3}{10}$

Fraction of the total distance to her grandmother's house was traveled on Sunday = $\frac{3}{10}$

Hence 3/10 of the total distance to her grandmother's house was traveled on Sunday

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3 years ago

I need answer Immediately pls!!!!!!

Illusion [34]

Given:

Total number of students = 27

Students who play basketball = 7

Student who play baseball = 18

Students who play neither sports = 7

To find:

The probability the student chosen at randomly from the class plays both basketball and base ball.

Solution:

Let the following events,

A : Student plays basketball

B : Student plays baseball

U : Union set or all students.

Then according to given information,

$n(U)=27$

$n(A)=7$

$n(B)=18$

$n(A'\cap B')=7$

We know that,

$n(A\cup B)=n(U)-n(A'\cap B')$

$n(A\cup B)=27-7$

$n(A\cup B)=20$

Now,

$n(A\cup B)=n(A)+n(B)-n(A\cap B)$

$20=7+18-n(A\cap B)$

$n(A\cap B)=7+18-20$

$n(A\cap B)=25-20$

$n(A\cap B)=5$

It means, the number of students who play both sports is 5.

The probability the student chosen at randomly from the class plays both basketball and base ball is

$\text{Probability}=\dfrac{\text{Number of students who play both sports}}{\text{Total number of students}}$

$\text{Probability}=\dfrac{5}{27}$

Therefore, the required probability is $\dfrac{5}{27}$ .

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2 years ago