Answer:
Step-by-step explanation:
Let's call hens h and ducks d. The first algebraic equation says that 6 hens (6h) plus (+) 1 duck (1d) cost (=) 40.
The second algebraic equations says that 4 hens (4h) plus (+) 3 ducks (3d) cost (=) 36.
The system is
6h + 1d = 40
4h + 3d = 36
The best way to go about this is to solve it by substitution since we have a 1d in the first equation. We will solve that equation for d since that makes the most sense algebraically. Doing that,
1d = 40 - 6h.
Now that we know what d equals, we can sub it into the second equation where we see a d. In order,
4h + 3d = 36 becomes
4h + 3(40 - 6h) = 36 and then simplify. By substituting into the second equation we eliminated one of the variables. You can only have 1 unknown in a single equation, and now we do!
4h + 120 - 18h = 36 and
-14h = -84 so
h = 6.
That means that each hen costs $6. Since the cost of a duck is found in the bold print equation above, we will sub in a 6 for h to solve for d:
1d = 40 - 6(6) and
d = 40 - 36 so
d = 4.
That means that each duck costs $4.
Answer:
All of the above
Step-by-step explanation:
A whole number and integers are numbers that don't have decimals.
A rational number is a number that can be written as a fraction
A real number is any number that is not complex, which means that it has an imaginary solution or imaginary number part of it.
2/5 is the answer unless your multiplying
Answer:
E ( 1 , -1 ) is in quadrant IV
Answer:
The statement is false
Step-by-step explanation:
we know that

The tangent function will be positive when the sine function and the cosine function have the same sign
so
In the first quadrant the tangent function is positive
In the third quadrant the tangent function is positive
so
The statement is false