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3 years ago

What is the length of the hypotenuse for a right triangle 11 and 60

Mathematics

1 answer:

Tom [10]3 years ago

5 0

Answer: 61

Step-by-step explanation:

First of all, a can be 11 and b can be 60 or other way around. Then, you use the formula to find the hypotenuse a2+b2=c2. Then, you substitute the given information: 11x11: 121, 60x 60: 3,600. Then add the answers: 121+3600=3721. Then do the square root of 3721 which is 61.

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The area of a rectangle is 48 square centimeters the length of the rectangle is 8 centimeters longer than the width? Which equat

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3 years ago

Triangle ABC is a right triangle. The length of the legs are 3 in and 6 in, how long is the hypotenuse? (Round to the nearest te

max2010maxim [7]

Triangle ABC is a right triangle. The length of the legs are 3 in and 6 in, how long is the hypotenuse? (Round to the nearest tenth if necessary)

When the two legs are given, the hypotenuse is found by using the Pythagorean Theorem, which states that:

$\displaystyle a^{2} +b^{2} =c^{2}$

In the theorem, a and b are the two legs, and c is the hypotenuse. Since you are given the length of the two legs, substitute it into the equation.

$a=3\\b=6$

$3^{2} +6^{2}=c^{2}$

Now, you need to square both 3 and 6. When you square a number, you're basically multiplying the number by itself.

$3^{2} =3 \times 3=9\\6^{2}=6 \times 6=36$

Substitute the numbers into the equation.

$9+36=c^{2}$

Add:

$45=c^{2}$

You're looking for the value of c, not c squared. To remove the square, you need to square root it.

$\displaystyle \sqrt{45}=\sqrt{c^{2} }$

Using a calculator, find the square root of 45.

$\displaystyle \sqrt{45}=\sqrt{c^{2} }\\c \approx 6.7$

The answer to your question is B) 6.7 inches.

7 0

3 years ago

Read 2 more answers

If ∠Q = 47°, then which of the following angles measures 47 degrees?

Tcecarenko [31]

Answer:

its 47 bc the demomenatir needs to be close to number 8

Step-by-step explanation:

hope dis helps

6 0

2 years ago

A certain freely falling object, released from rest, requires 1.50 s to travel the last 30.0 m before it hit the ground. a.Find

Lyrx [107]

A.)
s= 30m
u = ? ( initial velocity of the object )
a = 9.81 m/s^2 ( accn of free fall )
t = 1.5 s
s = ut + 1/2 at^2
\[u = \frac{ S - 1/2 a t^2 }{ t }\]
\[u = \frac{ 30 - ( 0.5 \times 9.81 \times 1.5^2) }{ 1.5 } \]
\[u = 12.6 m/s\]

b.)
s = ut + 1/2 a t^2
u = 0 ,
s = 1/2 a t^2
\[s = \frac{ 1 }{ 2 } \times a \times t ^{2}\]
\[s = \frac{ 1 }{ 2 } \times 9.81 \times \left( \frac{ 12.6 }{ 9.81 } \right)^{2}\]
\[s = 8.0917...\]
\[therfore total distance = 8.0917 + 30 = 38.0917.. = 38.1 m \]

4 0

4 years ago

Corey needs 24 boards that ate 47 1/ 2 inches long. How many feet of boards should he buy. Explain

Illusion [34]

If each board is going to be 47 and 1/2 inches long, and there'll be 24 of them, then their total is just their product.

keep in mind that there are 12 inches in 1 foot.

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\\\\\\
\stackrel{inches}{1140}\implies 1140~\underline{in}\cdot \cfrac{ft}{12~\underline{in}}\implies \cfrac{1140~ft}{12}\implies 95~ft$

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