Hello from MrBillDoesMath!
Answer:
All equations have two real roots.
Discussion:
The solutions of the quadratic ax^2 + bx + c = 0 are given by the formula:
x = (-b +\- sqrt(b^2-4ac) ) / (2a)
The key element is the discriminant, D, which equals (b^2-4ac)
For 2) a = 3, b = 4, c = -4, D = 4^2 - 4(3)(-4) = 16 + 48 = 64 > 0 so there are two real solutions
For 4) D = b^2 - 4ac = (-1)^2 - 4(6)(-1) = 1 + 24 = 25 >0 so there are two real solutions
For 6), a = -3, b = 12, c= -11, D = 12^2 - 4(-3)(-11) = 144 - 132 = 12 > 0 so
there are two real solutions
Thank you,
MrB
4,0
that is the ordered pair of the solution:)
Answer: B) 86°
Step-by-step explanation:
The angles of a triangle always add to equal 180.
So let's call the third angle x and add the other two angles with it.
32+62+x=180
94+x=180
Now we solve for x
Subtract 94 from both sides
94-94+x=180=94
x=86
The surface area of a sphere of radius r is A = 4π*r^3.
Since the radius in this case is 7 cm (half the 14 cm diameter), the area of this sphere is
A = 4π(7 cm)^2, or 196π cm^2.