Answer:
Probability that a car need to be repaired once = 20% = 0.20
Probability that a car need to be repaired twice = 8% = 0.08
Probability that a car need to be repaired three or more = 2% = 0.02
a) If you own two cars what is the probability that neither will need repair?
Probability that a car need to be repaired once , twice and thrice or more= 0.20+0.08+0.02=0.3
Probability that car need no repair = 1-0.3=0.7
Neither car will need repair=
b) both will need repair?
Probability both will need repair = 
c)at least one car will need repair
Neither car will need repair=
Probability that at least one car will need repair= 1-0.49 = 0.51
Answer:
b
Step-by-step explanation:
They do not intersect, they are parallel lines.
Answer:
32/20
Step-by-step explanation:
32 and 20 are both divisible by 4. 4*8=32 and 4*5=20. So this one works. Another way to think about it is if you put them as fractions and reduced them down to their simplest form, they would form the fraction 8/5.Oct 17, 2019
Answer: Graph B and Graph D