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rjkz [21]
3 years ago
6

To make the five standard solutions you will need for the Beer's Law Plot, you will first create a stock solution from ( NH 4 )

3 Fe ( ox ) 3 ⋅ 3 H 2 O . The stock solution is made using 125 mg of ( NH 4 ) 3 Fe ( ox ) 3 ⋅ 3 H 2 O dissolved in deionized (DI) water in volumetric glassware for a total volume of 25 mL. Calculate the concentration of the stock solution.
Chemistry
1 answer:
Cerrena [4.2K]3 years ago
5 0

Answer:

Concentration of stock solution in g/L = 5.0g/L

Concentration of stock solution in mol/L = 0.00117 mol/L or 0.00117 M

Explanation:

Concentration in mol/L = (Concentration in g/L)/(Molar mass)

Mass of (NH₄)₃Fe(ox)₃.3H₂O stock = 125mg = 0.125g

Volume of stock solution required = 25mL = 0.025 L

Concentration in g/L = 0.125/0.025 = 5.0 g/L

Molar Mass of (NH₄)₃Fe(ox)₃.3H₂O = (NH₄)₃Fe(C₂O₄)₃.3H₂O = 428.0632 g/mol

Concentration in mol/L = 5/428.0632 = 0.00117 mol/L = 0.00117 M

Hope this helps!!!

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solong [7]

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MnO₄⁻ + 5 Fe²⁺ + 8H⁺ → Mn²⁺ + 5 Fe³⁺ +  4H₂O

<em>Where 1 mole of permangante with 5 moles of Fe²⁺ and 8 moles of H⁺ produce 1 mole Mn²⁺, 5 of Fe³⁺ and  4 of H₂O</em>

<em />

If the diappearence of 1 mole has a rate of 4.0x10²mol/Ls, disappearence of 5 moles of Fe²⁺ and 8 moles of H⁺ have a rate of:

Fe²⁺ = 1 mole MnO₄⁻ × ( 4.0x10²mol/Ls / 5 moles of Fe²⁺) = 80mol/Ls

H⁺ = 1 mole MnO₄⁻ × ( 4.0x10²mol/Ls / 8 moles of H⁺) = 50mol/Ls

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H₂O = 1 mole MnO₄⁻ × ( 4.0x10²mol/Ls / 4 moles of H₂O) = 1.0x10²mol/Ls

7 0
3 years ago
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