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Nookie1986 [14]
3 years ago
8

How many formula units are present in 40.0 grams of Cu2S?

Chemistry
1 answer:
11Alexandr11 [23.1K]3 years ago
4 0

Never mind, I did the problem wrong, I deeply apologize.

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Select the correct pronoun.
ololo11 [35]
These are some pronouns to help you!

<span>I, me, he, she, herself, you, it, that, they, each, few, many, who, whoever, whose, someone, everybody.
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It is who! :D
I hope this helps!
3 0
3 years ago
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How fast did the universe expand?​
Sidana [21]

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Actually there is no answer but there is so much theories but people mostly says Bug Bang

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3 years ago
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Calculate the volume of 1 M NaOH needed to prepare 10.0 ml of a 0.10 M solution.
Mumz [18]
Answer is: <span>volume of 1 M NaOH is 1 ml.
</span>c₁(NaOH) = 1 M.
V₂(NaOH) = 10 ml.
c₂(NaOH) = 0,1 M.
V₁(NaOH) = ?
c₁ - original concentration of the solution, before it gets diluted.
c₂ - final concentration of the solution, after dilution.
V₁ - <span>volume to be diluted.
V</span>₂ - <span>final volume after dilution.
c</span>₁ · V₁ = c₂ · V₂.
V₁(NaOH) = c₂ · V₂ ÷ c₁.
V₁(NaOH) = 0,1 M · 10 ml ÷ 1 M.
V₁(NaOH) = 1 ml.
7 0
3 years ago
Substances have a fixed arrangement of atoms. true or false (NO LINKS PLEASE)
KATRIN_1 [288]

Answer:

True

Explanation:

5 0
3 years ago
How many milliliters of a 0.223 M KNO3 solution contain 0.250 moles of KNO3?
anyanavicka [17]

Answer:

1121.08 millilitres of 0.223 M KNO_{3} solution contains 0.250 moles of KNO_{3}.

Explanation:

The formula for molarity of a solution:

Molarity=\frac{n}{V}\\ where,n=number\: of\:moles\\V=volume\:of\:solution\:in\:L

Molarity = 0.223 M

n = 0.250 moles

V=\frac{n}{Molarity}=\frac{0.250}{0.223}=1.12108L=1121.08mL

Therefore, 1121.08 millilitres of 0.223 M  KNO_{3} solution contains 0.250 moles of  KNO_{3}.

6 0
3 years ago
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