Ask question

Ask question

All categories

3 years ago

7

Student price tickets to a movie are $1 and non-student tickets are $2. 350 tickets are sold and the total amount made is $450.

How many non-student tickets were sold?

1 answer:

Nastasia [14]3 years ago

5 0

S + n = 350.....s = 350 - n
s + 2n = 450

350 - n + 2n = 450
n = 450 - 350
n = 100 <=== there were 100 non-student tickets sold

You might be interested in

Help me with trigonometry

poizon [28]

Answer:

See below

Step-by-step explanation:

It has something to do with the<em> </em><u><em>Weierstrass substitution</em></u>, where we have

$\int\, f(\sin(x), \cos(x))dx = \int\, \dfrac{2}{1+t^2}f\left(\dfrac{2t}{1+t^2}, \dfrac{1-t^2}{1+t^2} \right)dt$

First, consider the double angle formula for tangent:

$\tan(2x)= \dfrac{2\tan(x)}{1-\tan^2(x)}$

Therefore,

$\tan\left(2 \cdot\dfrac{x}{2}\right)= \dfrac{2\tan(x/2)}{1-\tan^2(x/2)} = \tan(x)=\dfrac{2t}{1-t^2}$

Once the double angle identity for sine is

$\sin(2x)= \dfrac{2\tan(x)}{1+\tan^2(x)}$

we know $\sin(x)=\dfrac{2t}{1+t^2}$ , but sure, we can derive this formula considering the double angle identity

$\sin(x)= 2\sin\left(\dfrac{x}{2}\right)\cos\left(\dfrac{x}{2}\right)$

Recall

$\sin \arctan t = \dfrac{t}{\sqrt{1 + t^2}} \text{ and } \cos \arctan t = \dfrac{1}{\sqrt{1 + t^2}}$

Thus,

$\sin(x)= 2 \left(\dfrac{t}{\sqrt{1 + t^2}}\right) \left(\dfrac{1}{\sqrt{1 + t^2}}\right) = \dfrac{2t}{1 + t^2}$

Similarly for cosine, consider the double angle identity

Thus,

$\cos(x)= \left(\dfrac{1}{\sqrt{1 + t^2}}\right)^2- \left(\dfrac{t}{\sqrt{1 + t^2}}\right)^2 = \dfrac{1}{t^2+1}-\dfrac{t^2}{t^2+1} =\dfrac{1-t^2}{1+t^2}$

Hence, we showed $\sin(x) \text { and } \cos(x)$

======================================================

$5\cos(x) =12\sin(x) +3, x \in [0, 2\pi ]$

Solving

$5\,\overbrace{\frac{1-t^2}{1+t^2}}^{\cos(x)} = 12\,\overbrace{\frac{2t}{1+t^2}}^{\sin(x)}+3$

$\implies \dfrac{5-5t^2}{1+t^2}= \dfrac{24t}{1+t^2}+3 \implies \dfrac{5-5t^2 -24t}{1+t^2}= 3$

$\implies 5-5t^2-24t=3\left(1+t^2\right) \implies -8t^2-24t+2=0$

$t = \dfrac{-(-24)\pm \sqrt{(-24)^2-4(-8)\cdot 2}}{2(-8)} = \dfrac{24\pm 8\sqrt{10}}{-16} = \dfrac{3\pm \sqrt{10}}{-2}$

$t=-\dfrac{3+\sqrt{10}}{2}\\t=\dfrac{\sqrt{10}-3}{2}$

Just note that

$\tan\left(\dfrac{x}{2}\right) = \dfrac{3\pm 8\sqrt{10}}{-2}$

and $\tan\left(\dfrac{x}{2}\right)$ is not defined for $x=k\pi , k\in\mathbb{Z}$

6 0

2 years ago

Find the measure of each interior angle of a regular nonagon

Naddik [55]

Because the nonagon is regular, the angles are equal. Nona means nine. The total of the measures of the interior angles of any polygon is (n-2)180. Use this formula to find the measure of one interior angle.
(9-2)180
7*180=1260. Divide by 9 to get the measure of one angle.
1260/9=140

The answer is 140 :)

5 0

3 years ago

Read 2 more answers

The ratio of the lengths of corresponding sides of similar triangles is 3/8. What is the ratio (smaller to larger) of the areas?

svlad2 [7]

Answer:

9/64

Step-by-step explanation:

For similar triangles, the ratio of areas is the square of the ratio of corresponding sides.

__

The ratio of areas is (3/8)² = 9/64.

4 0

1 year ago

Two cyclists start from 98 miles apart and begin racing toward each

kati45 [8]

The speed of one bicyclist was 14.5mph, speed of the other bicyclist was 17.5mph.

Let the speed of one bicyclist=x mph

Let the speed of the other bicyclist=(x+3) mph

Hence:

Speed of one bicyclist:

3x+3(x+3)+2=98

3x+3x+9+2=98

6x=87

Divide both side by 6x

x=87/6

x=14.5 mph

Speed of the other bicyclist:

x+3 mph

14.5 mph+3 mph

=17.5 mph

Inconclusion the speed of one bicyclist was 14.5mph, speed of the other bicyclist was 17.5mph.

Learn more here:

brainly.com/question/18839894

3 0

2 years ago

Read 2 more answers

What fraction is £1 of 13p?

Rasek [7]

I believe it would be 13p im not for sure though

4 0

3 years ago