What two consecutive whole numbers lie between the square root of 55?

2 answers:

6 0

$\boxed{7 \ \textless \ \sqrt{55} \ \textless \ 8}\\\\because\ 7^2=49 \ \textless \ 55\ and\ 8^2=64 \ \textgreater \ 55$

Orlov [11]2 years ago

6 0

By using directly calculators that are capable of solving for square roots, we know that the value of the square root of 55 is approximately equal to 7.42. The whole numbers that are directly to the left and right of 7.42 in a number line are 7 and 8. Thus, the answer is 7 and 8.

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In the diagram below, GH is parallel to DE . If GH is 3 more than EH FH=10, and DE=12 find the length of EH. Figures are not nec

steposvetlana [31]

Answer: 5

Step-by-step explanation:

Since $\overline{GH} \parallel \overline{DE}$ , by the corresponding angles theorem, $\angle FGH \cong \angle FDE, \angle FHG \cong \angle FED$ . This means $\triangle FGH \sim \triangle FDE$ by AA.

As corresponding sides of similar triangles are proportional,

$\frac{10}{x+3}=\frac{10+x}{12}\\(10)(12)=(10+x)(x+3)\\120=x^{2}+13x+30\\x^{2}+13x-90=0\\(x+18)(x-5)=0\\x=-18, 5$
However, as distance must be positive, we consider the positive solution, x=5.