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3 years ago

What two consecutive whole numbers lie between the square root of 55?

2 answers:

6 0

$\boxed{7 \ \textless \ \sqrt{55} \ \textless \ 8}\\\\because\ 7^2=49 \ \textless \ 55\ and\ 8^2=64 \ \textgreater \ 55$

Orlov [11]3 years ago

6 0

By using directly calculators that are capable of solving for square roots, we know that the value of the square root of 55 is approximately equal to 7.42. The whole numbers that are directly to the left and right of 7.42 in a number line are 7 and 8. Thus, the answer is 7 and 8.

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∠xangle, x and \angle y∠yangle, y are supplementary angles. \angle y∠yangle, y measures 97^\circ97 ∘ 97, degrees. What is the me

gtnhenbr [62]

Answer:

83°

Step-by-step explanation:

Since angle x and angle y are supplementary angles,

x + y = 180°.

Since y = 97°

x = 180° - y = 180° - 97° = 83°

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3 years ago

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riadik2000 [5.3K]

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3 years ago

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3 years ago

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On a trip, a motorist drove 150 miles in the morning and 50 miles in the afternoon. His average rate in the morning was twice hi

Lina20 [59]

Answer:

Morning's average rate = 50 mph, and Afternoon's average rate = 25 mph.

Step-by-step explanation:

Suppose he drove 150 miles for X hours, then his average rate in the morning was (150/X) mph.

Given that he spent 5 hours in driving.

And he drove 50 miles for (5-X) hours, then his average rate in the afternoon was 50/(5-X) mph.

Given that his average rate in the morning was twice his average rate in the afternoon.

(150/x) = 2 * 50/(5-x)

150/x = 100/(5-x)

Cross multiplying terms, we get:-

150*(5-x) = 100*x

750 - 150x = 100x

750 = 100x + 150x

750 = 250x

x = 750/250 = 3.

It means he spent 3 hours in the morning and 2 hours in the afternoon.

So morning's average rate = 150/3 = 50 mph.

and afternoon's average rate = 50/(5-3) = 25 mph.

8 0

3 years ago

Helpp!!<br> Simplify : [( 4 1/6 + 2 1/3 ) ÷ 4 1/3 ] - 1 1/2

Nadusha1986 [10]

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{0}}}}}$

Step-by-step explanation:

$\sf{ [ (4 \frac{1}{6} + 2 \frac{1}{3} ) \div 4 \frac{1}{3}] - 1\frac{1}{2} }$

Convert the mixed numbers into improper fraction

$\longrightarrow{ \sf{ [ ( \frac{25}{6} + \frac{7}{3} ) \div \frac{13}{3}] - \frac{3}{2}}}$

Add the fractions : 25 / 6 and 7 / 3

While performing addition or subtraction of unlike fractions, you have to express the given fractions into equivalent fractions of common denominator and add or subtract as we do with like fraction.

To do so, first take the L.C.M of 6 and 3 which results to 6

$\longrightarrow\sf{ [( \frac{25 + 7 \times 2}{6} ) \div \frac{13}{3} ] - \frac{3}{2}}$

$\longrightarrow{ \sf{ [( \frac{25 + 14}{6} ) \div \frac{13}{3} ] - \frac{3}{2} }}$

$\longrightarrow{ \sf{ [ \frac{39}{6} \div \frac{13}{3}] - \frac{3}{2} }}$

Multiply the dividend by the reciprocal of the divisor.

Reciprocal of any number or fraction can be obtained by interchanging the position of numerator and denominator

$\longrightarrow{ \sf{ [ \frac{39}{6} \times \frac{3}{13} ] - \frac{3}{2}}}$

To multiply one fraction by another, multiply the numerators for the numerator and multiply the denominators for its denominator and reduce the fraction obtained after multiplication into lowest term

$\longrightarrow{ \sf{ [ \frac{39 \times 3}{6 \times 13} ] - \frac{3}{2}}}$

$\longrightarrow{ \sf{ [ \frac{117}{78} ] - \frac{3}{2} }}$

$\longrightarrow{ \sf{ \frac{3}{2} - \frac{3}{2} }}$

While performing the addition or subtraction of like fractions , you just have to add or subtract the numerator respectively in which the denominator is retained same

$\longrightarrow{ \sf{ \frac{3 - 3}{2} }}$

Subtract 3 from 3

$\longrightarrow{ \sf{ \frac{0}{2}}}$

Divide 0 by 2

$\longrightarrow{ \sf{0}}$

Hope I helped!

Best regards!

3 0

3 years ago