The measurement of ∠KNL is 102°
First, you must set up an equation to find x.
Then, you must simplify both sides of the equation.
Next, subtract 3x on both sides.
Then, subtract 2 on each side.
Next, divide 2 on each side.
Now that we have the value of x, we can substitute it in for angle KNL.
![[3(20+14)]](https://tex.z-dn.net/?f=%5B3%2820%2B14%29%5D)
![[3(34)]](https://tex.z-dn.net/?f=%5B3%2834%29%5D)
°
The solution to given system of equations is x = 2 and y = -5
<em><u>Solution:</u></em>
<em><u>Given the system of equations are:</u></em>
4x + y = 3 ---------- eqn 1
-2x + 3y = -19 ---------- eqn 2
We have to find the solution to above system of equations
<em><u>We can solve the system by substitution method</u></em>
From eqn 1,
4x + y = 3
Isolate y to one side
y = 3 - 4x ----------- eqn 3
<em><u>Substitute eqn 3 in eqn 2</u></em>
-2x + 3(3 - 4x) = -19
-2x + 9 - 12x = -19
Combine the like terms
-14x = -19 - 9
-14x = -28
Divide both sides of equation by -14
<h3>x = 2</h3>
<em><u>Substitute x = 2 in eqn 3</u></em>
y = 3 - 4(2)
y = 3 - 8
<h3>y = -5</h3>
Thus the solution is x = 2 and y = -5
I: 12x-5y=0
II:(x+12)^2+(y-5)^2=169
with I:
12x=5y
x=(5/12)y
-> substitute x in II:
((5/12)y+12)^2+(y-5)^2=169
(25/144)y^2+10y+144+y^2-10y+25=169
(25/144)y^2+y^2+10y-10y+144+25=169
(25/144)y^2+y^2+144+25=169
(25/144)y^2+y^2+169=169
(25/144)y^2+y^2=0
y^2=0
y=0
insert into I:
12x=0
x=0
-> only intersection is at (0,0) = option B
2.5x7( days in a week) = 17.5 and since its falling it would be negative
