What is the maximum value of h(t)=−16t^2+32t+64
1 answer:
Answer:
Step-by-step explanation:
h(t)=-16t²+32t+64
=-16(t²-2t)+64
=-16(t²-2t+1-1)+64
=-16(t-1)²+16+64
=-16(t-1)²+80
maximum value=80 and is obtained at t=1
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The length would be 230, and the width would be 170, and since there are 4 sides there would be 2 of each. So 230x2=460 and 170x2=340. 460+340= 800
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