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nirvana33 [79]
3 years ago
14

Plot C(-1,–7), D (6,–7), E(5,3), and F(5,-5) in a coordinate plane. Are CD and EF congruent?

Mathematics
1 answer:
N76 [4]3 years ago
7 0

Answer:

No, they are not congruent

Step-by-step explanation:

By CD and EF being congruent, we want to know if they are equal.

What we can simply do here is to find the distance between the points present.

That is, the distance between C and D, the distance between E and F

To get the distances between two points , we use the following equation

D = √(x2-x1)^2 + (y2-y1)^2

For CD, we have

D = √(6 -(-1)^2 + (-7 + 7)^2

D = √(7)^2 = 7 units

For EF, we have

D = √(5-5)^2 + (-5-3)^2

D = √(-8)^2

D = √(64) = 8 units

This clearly shows that they are both not congruent

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The likelihood that a patient with a heart attack dies of the attack is 0.04 (i.e., 4 of 100 die of the attack). Suppose we have
Sonbull [250]

The probability solved by binomial distribution that all will survive is 0.8154.

<h3>What is Binomial distribution? </h3>

When each trial has the same probability of achieving a given value, the number of trials or observations is summarized using the binomial distribution. The likelihood of observing a specific number of successful outcomes in a specific number of trials is determined by the binomial distribution.

Computation of probability of all survived people from heart attack;

A heart attack patient has a 0.04 percent chance of dying from the attack (i.e., 4 of 100 die of the attack).

What is the likelihood that each of the five patients who experience a heart attack will survive?

We'll refer to a victory in this scenario as a heart attack (p = 0.04). In other words, we are interested in the likelihood that none of our n=5 patients will die (0 successes).

Each attack has a chance of being fatal or not, with a probability of 4 percent for all patients, and each patient's result is independent.

Assume for the purposes of this example that the five individuals being examined are unrelated, of the same age, and free of any concomitant disorders.

By binomial distribution,

\begin{gathered}P(0 \text { successes })=\frac{5 !}{0 !(5-0) !} 0.04^{0}(1-0.04)^{5-0} \\P(0 \text { successes })=\frac{5 !}{5 !}(1)(0.96)^{5}=(1)(1)(0.8154)=0.8154\end{gathered}

Therefore, with a 4 % chance that anyone will die, there is an 81.54% chance that every patient will survive the onslaught. The outcomes in this example could be 0, 1, 2, 3, 4 or 5 successes (fatalities).

To know more about Binomial Distribution, here

brainly.com/question/27794898

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6 0
2 years ago
Twelve more than the quotient of six divided by three
dezoksy [38]
Hey You!

The Expression Is: (6 ÷ 3) + 12
3 0
3 years ago
A skatepark has an area of 6000ft2, a length of 60 ft and an unknown width, find the width of the skatepark
aliya0001 [1]

Answer:

The width of the skatepark is 100ft^2.

Step-by-step explanation:

Total area= 6000ft^2

The Formula for area= L x W (depends on the shape, but in this case that is the formula)

Length= 60 ft

Width = 100

60 x 100= 6000ft^2

Hope this helped!

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A scale drawing of a lake has a scale of 1 cm to 80 m. If the actual width of the lake is 1,000 m, what is the width of the lake
7nadin3 [17]

The width of the lake on the scale drawing is 12.5m

<h3>Scale drawing</h3>

A scale drawing is an enlargement of an object. Given that the scale drawing of a lake has a scale of 1 cm to 80 m, then;

1cm = 80m

If the actual width of the lake is 1,000 m, then the lake on the scale is as shown;

Lake on the scale = 1000/80

Lake on the scale = 12.5cm

Hence the width of the lake on the scale drawing is 12.5m

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