Answer:
A has 77 grams and B has 12 grams.
Step-by-step explanation:
In order to find the amount of fat in both, we need to set up two equations in standard form. First, we can set up one comparing the two amounts and solve for the constant.
A = 6B + 5
A - 6B = 5
Now we can create one using the difference of the two.
A - B = 65
To solve, we now multiply the second equation by -1 and solve for B.
A - 6B = 5
-A + B = -65
----------------
-5B = -60
B = 12
Knowing this we can plug into the equation and find the value of A.
A - B = 65
A - 12 = 65
A = 77
Answer:
x(x-3)(x+2)
Step-by-step explanation:
x^3-x^2-6x
First subsitute out x:
x(x^2-x-6)
Find the multiples of the x's:
x(x-3)(x+2)
Answer:
(0, inf)
Step-by-step explanation:
The average rate of change of a function is related to it's first derivative. When the first derivative is positive, the average rate of change is positive, which means that the function is crescent.
Now, when the first derivative is negative, the average rate of change will be negative too, and the function is going to be decrescent.
In your function.
We have: f'(x) = 2x
2x > 0 when x > 0. So when x > 0 the average rate of change of your function is positive, and it's values increases as the time increases. When x < 0, the average rate of change is negative, so, as the time increases, the values of f decrease.
You can use a graphic tool to plot f and visualize this better.
Answer: Yes , the accuracy rate appear to be acceptable .
Step-by-step explanation:
Let p be the population proportion of the orders that were not accurate .
Then according to the claim we have ,

Since the alternative hypothesis is two-tailed so the hypothesis test is a two-tailed test.
For sample ,
n = 391
Proportion of the orders that were not accurate =
Test statistics for population proportion :-

By using the standard normal distribution table,
The p-value : 
Since the p-value is greater that the significance level (0.05), so we do not reject the null hypothesis.
Hence, we conclude that the accuracy rate appear to be acceptable.