Answer: tea = 15 rupees per kg
sugar= 3 rupees per kg
Step-by-step explanation:
Hi, to answer this question we have to write a system of equations with the information given:
<em>"Two kg of tea and 3 kg of sugar cost rupees 39 in january 1997":
</em>
2 t + 3 s =39 (a)
Where:
- t= price of 1 kg of tea
- s = price of 1 kg of sugar
<em>"in march 1997 the price of the tea increased by 25% (1.25)and the price of the sugar increased by 20%(1.20) and the same quantity of tea and sugar cost rupees 48.30.
"</em>
2(t1.25)+3(s1.2) = 48.30 (b)
- <em>Solving for t in (b)
</em>
2t =39-3s
t = (39 -3s)/2
t = 19.5-1.5s
- <em>Replacing the value of t in (b)
</em>
2 x ((19.5-1.5s)1.25)+ 3 ( 1.2s) =48.30
2x ( 24.375 -1.875s) +3.6s =48.30
48.75 -3.75s+3.6s= 48.30
48.75-48.30 = 3.75s-3.6s
0.45= 0.15s
0.45/0.15 =s
3 =s
- <em>Replacing the value of s in (a)
</em>
2 t + 3 (3) =39
2 t + 9 =39
2 t =39 -9
2 t =30
t = 30/2
t= 15
Prices in january:
tea = 15 rupees per kg
sugar= 3 rupees per kg
Feel free to ask for more if needed or if you did not understand something.
Answer: 17
21-4=17
4+17=21
21+17=38 and so on..
Answer:
rom the relation for linear regression formula, Y = b·X + a, we have ;
For car 1
ΣXY = 102780
(ΣX)² = 36
ΣX = 6
ΣY = 52390
ΣX² = 14
N = 3
b = -1000
a = 19463
Y = -1000×X + 19463
For Car 2
ΣXY = 102539.8
(ΣX)² = 36
ΣX = 6
ΣY = 52346.6
ΣX² = 14
N = 3 .
b = -1076.7
a = 19602
Y = -1076.7×X + 19602
Step-by-step explanation:
part B ^
Answer:
1/4 of a pie
Step-by-step explanation:
2 / 8 = 1/4
Answer:
The diagonals are congruent.
Step-by-step explanation:
