S=2d
4s+3d=300000-80000
4s+3d=220000, now using s=2d in this equation you get:
4(2d)+3d=220000
8d+3d=220000
11d=220000
d=20000
So each daughter gets 20000 and each son gets 40000.
Answer:
D . P(x)=-0.5
Step-by-step explanation:
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Answer:
a. 55.56%
b. 44.44%
c. 3.33%
d. 33.33%
Step-by-step explanation:
total supply = 180
a. In the first factory the total number obtained = 100
probability that the chosen part is from the first
= 100/180
= 0.5556
= 55.56%
b. In the second factory total = 80
probability that the chosen part is from the second
= 80/180
= 0.4444
= 44.44%
c. probability that part chosen at random from 180 is defective
= 2% * 0.5556 + 5% * 0.4444
= 0.02*0.5556 + 0.05*0.4444
= 0.011112 + 0.0222
= 0.03331
= 3.33%
d. probability it came rom the first factory if it is defective

= 
= 
= 0.33357
= 33.33%
Answer:
See answer and graph below
Step-by-step explanation:
∬Ry2x2+y2dA
=∫Ry.2x.2+y.2dA
=A(2y+4Ryx)+c
=∫Ry.2x.2+y.2dA
Integral of a constant ∫pdx=px
=(2x+2.2Ryx)A
=A(2y+4Ryx)
=A(2y+4Ryx)+c
The graph of y=A(2y+4Ryx)+c assuming A=1 and c=2